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laiz [17]
3 years ago
8

Solve |y + 2| > 6 i dont understand this, please help

Mathematics
1 answer:
Lisa [10]3 years ago
7 0

y < - 8  or y > 4

inequalities of the form | x | > a always have solutions of the form

x < - a or x > a

we have to solve

y + 2 < - 6 or y + 2 > 6

y + 2 < - 6 ( subtract 2 from both sides )

y < - 8

or

y + 2 > 6 ( subtract 2 from both sides )

y > 4

these can be combined using interval notation

y ∈ (- ∞, - 8 ) ∪ (4, ∞ )

As a check

substitute chosen values of x from each interval

y = - 10 :  | - 10 + 2 | = | - 8 | = 8 > 6 this is true

y = 12 : | 12 + 2 | = | 14 | = 14 > 6 which is also true



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Answer:

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Step-by-step explanation:

2(7x - 1)

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Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

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6 0
3 years ago
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:) please help me. Thank you
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Answer:

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Step-by-step explanation:

i used m ath way

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