Sin (5/6) show work for circle

Musya8 [376]

There is a trig identity called the sum of 2 angles for sin its
sin(a+b)=sin(a)cos(b)+cos(a)(sin(b)

You will need to use it. So in your question split the 4x in 2 equal parts 2x and 2x

sin(4x)=sin(2x+2x)

Now using the expansion above you will get

sin(2x+2x)=sin(2x)×cos(2x)+cos(2x)×sin(2x)

And it will simplify to

2sin(2x)cos(2x)

I hope this helps you! Good luck :)

5 0

3 years ago

Read 2 more answers

An elevator ascends,or goes up,at a rate of 750 feet per minute.is the height to which the elevator ascend proportional to the n

Sliva [168]

C=480
solve

480=24n+35
minus 35 both sides
445=24n
divide both sides by 24
18.541666666666666666666666666667=n

so about 18 cakes

7 0

4 years ago

Find the total cost of a $32 Uber ride with a 15% tip.

jasenka [17]

Answer:

$36.8

Step-by-step explanation:

i just calculated it!

32*15% = 4.8

32+4.8= 36.8

7 0

3 years ago

A woman spent two thirds of her money she lost two thirds the remainder and then had $4 left how much money did she start with

Lisa [10]

Answer

Find out how much money did she start with.

To proof

let us assume that the money she had be x.

As given

woman spent two thirds of her money

$Money\ spent = \frac{2x}{3}$

Money she had after spent two thirds of her money = Total money - money spent

$= x - \frac{2x}{3}$

$= \frac{1x}{3}$

As given she lost two thirds the remainder

$=\frac{2}{3}\times ( money\ she\ had\ after\ spending\ two\ thirds\ of\ her\ money)$

$= \frac{2}{3} \times\frac{1x}{3}$

we get

$=\frac{2x}{9}$

Money she had after lost two thirds the remainder = Money she had after spent two thirds of her money - she lost two thirds the remainder

$= \frac{1x}{3} - \frac{2x}{9}$

$= \frac{1x}{9}$

As given

she had $4 left

thus

$\frac{1x}{9} = 4$

x = $36

she start with $36.

Hence proved

3 0

4 years ago

Read 2 more answers

Shayla has 6 1/2 pounds of potato salad into containers each of which holds 1 5/8 pounds. How many containers does she need?

Oksi-84 [34.3K]

let's firstly convert the mixed fractions to improper fractions and then divide.

$\bf \stackrel{mixed}{6\frac{1}{2}}\implies \cfrac{6\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{13}{2}}~\hfill \stackrel{mixed}{1\frac{5}{8}\implies \cfrac{1\cdot 8+5}{8}}\implies \stackrel{improper}{\cfrac{13}{8}} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{total salad}}{\cfrac{13}{2}}\div \stackrel{\stackrel{\textit{conainer's}}{\textit{capacity}}}{\cfrac{13}{8}}\implies \cfrac{\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{\underset{1}{\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}}\cdot \cfrac{\stackrel{4}{\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}}{\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies 4$

6 0

4 years ago