$\bf \begin{cases}
x=-1\implies &x+1=0\\
x=0\implies &x=0
\end{cases}
\\\\\\
\stackrel{\textit{multiplicity of 3}}{(x+1)^3}~~\stackrel{\textit{multiplicity of 1}}{(x)^1}=\stackrel{original~polynomial}{0}
\\\\\\
(x^3+3x^2+3x+1)(x)=\stackrel{y}{0}\implies x^4+3x^3+3x^2+x=y$

6 0

3 years ago

John has 12 marbles of different colors, including one red, one green, and one blue marble. in how many ways can he choose 4 mar

Savatey [412]

3 ways (uncertain)
1 red or blue or green + 3 other colours

7 0

3 years ago

Read 2 more answers

Find the minimum and maximum possible areas of a rectangle measuring 6 km by 11 km.

ExtremeBDS [4]

Assuming your numbers are rounded to the nearest km, the minimum area will be ...
(5.5 km)·(10.5 km) = 57.75 km² . . . minimum

And the maximum area will be ...
(6.5 km)·(11.5 km) = 74.75 km² . . . maximum

_____
When a number is rounded to 6 km as the nearest km, its value may actually be anywhere in the range 6 km ± 0.5 km. If you really want to get technical about it, the ranges of possible dimensions are [5.5, 6.5) km and [10.5, 11.5) km, and the range of possible areas is [57.75, 74.75) km².

3 0

3 years ago

I will mark brainlyist if you answer it and it is correct

Stells [14]

Hello!

You can solve this algebraically

7w < -42

Divide both sides by 7

w < -6

The answer is any number less than -6 or w < -6

Hope this helps!

7 0

3 years ago

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5 more than the sum of p and a​

5 more than the sum of p and a