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Setler79 [48]
3 years ago
13

Use the properties of equality to finish solving the equation. 3 4 (20y − 8) + 5 = 1 2 y + 1 4 (20y + 8) 1. Distribute the 3 4 a

nd 1 4 : 2. Combine like terms: 15y − 6 + 5 = 1 2 y + 5y + 2 15y − 1 = 11 2 y + 2 What is the solution?
Mathematics
2 answers:
Lady_Fox [76]3 years ago
8 0

Answer:

6/9

Step-by-step explanation:

Orlov [11]3 years ago
3 0

Answer:

The solution of the equation is y = 6/19

Step-by-step explanation:

Seems the division signs are omitted. The correct equation is given below.

The equation is:

3/4 (20y − 8) + 5 = 1/2 y + 1/4 (20y + 8)  

1. Distribute 3/4 and 1/4, so that we get

15y - 6 + 5 = 1/2y + 5y + 2

2. Combine like terms, we get

15y - 1 = 11/2 y +2

Now, we will collect like terms

15y - 11/2 y = 2 + 1

This can properly written as

15y - \frac{11}{2}y = 2 + 1

\frac{30y - 11y}{2} = 3

\frac{19y}{2}  = 3

Then,

19y = 2 \times 3

19y = 6

∴ y = 6/19

Hence, the solution of the equation is y = 6/19.

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At the rate of winning, they should win 44 games in  normal 110-game season.

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3 years ago
Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator. 16 yr to 20 yr
Ugo [173]
4/5

just take 16/20 and divde both be 4
5 0
3 years ago
The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

8 0
3 years ago
Factor x^2+6x-16 into the form (x+a)(x-b), what is a and b?
vfiekz [6]

Answer:

a=-8 b=2

Step-by-step explanation:

x^2+6x-16

x^2+(8-2)x-16=0

x^2+8x-2x-16=0

X(X+8)-2(X+8)=0

(X+8)(x-2)=0

Compare with (X+a)(X+b)

Where we get a=-8 b=2

8 0
3 years ago
Determine the values of h and k in the equation of g(x).
Arlecino [84]

Answer:

there is no answer

Step-by-step explanation:

8 0
3 years ago
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