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Furkat [3]
3 years ago
13

Which best describes Darwin's studies that led to the theory of evolution?​

Biology
2 answers:
const2013 [10]3 years ago
6 0
Do you have a picture of the question?


If not the Darwinism is a theory of Biloxi all evolution developed by the English naturalist Charles Darwin and others stating that all species of organism arise and develop through the natural selection of small, inherited variations that increase the individual’s ability to compete, survive and reproduce
iris [78.8K]3 years ago
3 0

Answer:

extensive research of an individual organism over many years

Explanation:

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Looking at the Punnett square, what are the possible genotypes and frequencies
Rom4ik [11]

Answer:

50% or 1/2 of the children will be heterozygous.

50% or 1/2 of the children will be recessive hom0zygotic.

Explanation:

7 0
3 years ago
What happens in the G2 phase of the cell cycle?
muminat
Your answer is After DNA replication, the cell leaves S phase and enters G2, when the cell prepares for mitosis or meiosis. At the G2 checkpoint, the cell checks two things. First, it checks DNA for any damage that might have occurred during replication. It also ensures all the proteins needed for cell division are present.
7 0
3 years ago
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Maru [420]
B explained is that idek I just need points
5 0
2 years ago
Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m
Vanyuwa [196]
This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

<span>Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
v=\frac{2\pi{r}}{T}
</span>=\frac{2\pi{r}}{1.88*365.25*86400} m/s, accounting for leap years
=3.371*10^{-8}\pi{r}   m/s

The centripetal force, Fc, generated is
Fc=\frac{mv^2}{r}   
        where m=mass of mars = 6.39*10^(24) kg
=\frac{mv^2}{r}
=\frac{6.39*10^{24}v^2}{r}
=7.26168*10^9\pi^2r

The gravitation pull from the sun, Fg, is given by
Fg=\frac{GMm}{r^2}
    where G=grav. const., =6.67408*10^(-11) m^3<span> kg^(</span>-1)<span> s^(</span>-2)
              M=mass of sun=1.989*10^(30) kg
=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}
=\frac{8.4826*10^44}{r^2}

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}
Solving for the real root:
r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}
=\frac{1.1681263*10^{35}}{\pi^2}
=2.279*10^11 m


5 0
3 years ago
Pls help ASAP plss need help​
DanielleElmas [232]

Answer:

1- D,C,A,B,E- 2 - B,A,C,D- 3- C,D,B,A.

Explanation:

8 0
3 years ago
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