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zzz [600]
3 years ago
9

Simplify (6x^-2)^2(0.5x)^4 show work please

Mathematics
2 answers:
tester [92]3 years ago
4 0
(6x^-2)^2(0.5x)^4 = (6^2)(x^-2(2))(1/2)^4(x^4) = 36x^-4(1/16x^4) = (36/16)x^(-4+4) = 9/4
Darina [25.2K]3 years ago
3 0

Answer:

(6x^{-2})^2(0.5x)^4=\frac{9}{4}

Step-by-step explanation:

The given equation is:

(6x^{-2})^2(0.5x)^4

Simplifying the above given equation, we get

=(36x^{-4})(\frac{1}{2}x)^4

=36x^{-4}(\frac{1}{16})x^4

=\frac{36}{16}x^{-4+4}

=\frac{36}{16}

=\frac{9}{4}

Thus, (6x^{-2})^2(0.5x)^4=\frac{9}{4}

which is the requires simplified form.

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Using the t-distribution, the t-statistic for the two-sided test would be of t = 0.7.

<h3>What is the test statistic for a t-distribution hypotheses test?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the expected value.
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The values of the parameters are given as follows:

\mu = 22, s = 7.043, n = 6.

The sample mean is:

\overline{x} = \frac{23 + 35 + 17 + 30 + 20 + 19}{6} = 24

Hence the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{24 - 22}{\frac{7.043}{\sqrt{6}}}

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∠E and ∠F are vertical angles with m∠E=9x+12 and m∠F=3x+24. What is the value of x?
statuscvo [17]

Answer:

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Step-by-step explanation:

<em>Vertical angles are equal as per definition.</em>

  • ∠E and ∠F are vertical angles
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  • x = ?

<u>Solution</u>

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