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4 years ago

Find the equation of the circle: b with center (5, 1/4 ), radius 6

Mathematics

1 answer:

PolarNik [594]4 years ago

6 0

The equation of the circle would be

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Find the coordinates of the vertices of the figure after the given transformation: T<0,7>

valentina_108 [34]

Answer:

Option A.

Step-by-step explanation:

The general transformation works as follows:

T<a,b>(x, y) = (x + a, y + b)

Then for our transformation, we will have:

T<0,7>(x, y) = (x, y + 7)

So now that we know how the transformation works, we need to apply it to the vertices.

Looking at the graph we can see that the vertices are:

X = (-4, -5)

W = (-3, -3)

L = (-5, -2)

Then the new points will be:

X' = (-4, - 5 + 7) = (-4, 2)

W' = (-3, -3 + 7) = (-3, 4)

L' = (-5, -2 + 7) = (-5, 5)

Then the correct option is A.

3 0

3 years ago

Look at the image below

Delvig [45]

Answer:

117.8

Step-by-step explanation:

Surface area = πr²+πrl (whee r = radius and l = slant height)

= π×3²+π×3×9.5

= 75π/2

= 117.8

8 0

3 years ago

Seven less than a number divided by 5 is -2

Black_prince [1.1K]

Answer:

Step-by-step explanation:

a number

a number divided by 5

x/5

Seven less than a number divided by 5

x/5 - 7

Seven less than a number divided by 5 is -2

x/5 - 7 = -2

x/5 = -2 + 7

x/5 = 5

x = 5 * 5

5 0

3 years ago

Read 2 more answers

Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

3 years ago

A sail is in the form of a right triangle that is four times as high as it is wide. The sail is made from 8 square meters of mat

Sedbober [7]

Answer:

I DON'T KNOW PLEASE PLEASE TELL

4 0

3 years ago