<u>Answer:</u> The correct answer is Nitrogen.
<u>Explanation:</u>
Electronic configuration is the representation which helps in determination of the total number of electrons and valence electrons that are present in an element.
For the given options:
<u>Option 1:</u> Carbon having atomic number 6
Electronic configuration of C = 
It has 2 electrons in its p-orbital.
<u>Option 2:</u> Oxygen having atomic number 8
Electronic configuration of O = 
It has 4 electrons in its p-orbital.
<u>Option 3:</u> Nitrogen having atomic number 7
Electronic configuration of N = 
It has 3 electrons in its p-orbital.
<u>Option 4:</u> Beryllium having atomic number 4
Electronic configuration of Be = 
It has 0 electrons in its p-orbital.
From the above information, the correct answer is Nitrogen.