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juin [17]
2 years ago
11

For the balanced equation shown below, what would be the limiting reagent if 93.9grams

Chemistry
1 answer:
svlad2 [7]2 years ago
5 0

Answer: A. C2H3F

Explanation:

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Which organism has the following characteristics: heterotrophic, eukaryotic,
Soloha48 [4]

This organism is Fungi, which can either be unicellular or multicellular, and has the only cell wall made of chitin out of the four.

6 0
2 years ago
How much carbon dioxide will be formed if 12.5 grams of oxygen reacts with 7.2 grams of propane (C3H8 )? Balanced equation: C3H8
solong [7]

Answer:

10.3125 grams of carbon dioxide will be formed.

Explanation:

The balanced reaction is:

C₃H₈ + 5 O₂→ 3 CO₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles participate in the reaction:

  • C₃H₈: 1 mole
  • O₂: 5 moles
  • CO₂: 3 moles
  • H₂O: 4 moles

Being the molar mass of the compounds:

  • C₃H₈: 44 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

then by stoichiometry of the reaction, the following amounts of mass participate in the reaction:

  • C₃H₈: 1 mole* 44 g/mole = 44 g
  • O₂: 5 moles* 32 g/mole= 160 g
  • CO₂: 3 moles* 44 g/mole= 132 g
  • H₂O: 4 moles* 18 g/mole= 72 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: If by reaction stoichiometry 44 grams of propane react with 160 grams of oxygen, 7.2 grams of propane react with how much mass of oxygen?

mass of oxygen=\frac{7.2 grams of propane*160 grams of oxygen}{44 grams of propane}

mass of oxygen= 26.18 grams

But 26.18 moles of O₂ are not available, 12.5 grams are available. Since you have less mass than you need to react with 7.2 grams of propane, oxygen O₂ will be the limiting reagent.

Then you can apply the following rule of three: if by stoichiometry of the reaction 160 grams of oxygen form 132 grams of carbon dioxide, 12.5 grams of oxygen will form how much mass of carbon dioxide?

mass of carbon dioxide=\frac{12.5 grams of oxygen*132 grams of carbon dioxide}{160 grams of oxygen}

mass of carbon dioxide= 10.3125 grams

<u><em>10.3125 grams of carbon dioxide will be formed.</em></u>

<u><em> </em></u>

<u><em></em></u>

7 0
2 years ago
How can crossing over lead to the expression Of new traits
Kamila [148]

Answer:

Crossing over, or recombination, is the exchange of chromosome segments between nonsister chromatids in meiosis. Crossing over creates new combinations of genes in the gametes that are not found in either parent, contributing to genetic diversity.

Explanation:

8 0
3 years ago
Which of the following series of isoelectronic ions (Mg²⁺, N³⁻, F⁻, Si⁴⁺) has the ionic radii in order of largest to smallest? A
Rom4ik [11]

Answer:

Option (d) is correct

N³⁻ > F⁻ > Mg²⁺ > Si⁴⁺

Explanation:

Total electrons for all the species = 10

So these are <u>iso electronic</u> with each other.

We know

Ionic radii ∝ \frac{Magnitude of Negative Charge}{Magnitude of Positive Charge}

  • Si⁴⁺ has 14 protons and 10 electrons
  • Mg²⁺ has 12 protons and 10 electrons
  • N³⁻ has 7 protons and 10 electrons
  • F⁻ has 9 protons and 10 electrons
  • Iso electronic species with greatest number of protons have small size and vice versa.
  • So Si⁺⁴ have smallest size and N³⁻ have largest in size
4 0
3 years ago
How many moles are there in 78.3g of CO2?
oksano4ka [1.4K]
The molar mass of CO2 can be calculated as follows;
CO2 — 12 + (16x2) = 12+ 32 = 44 g
Therefore molar mass of CO2 is 44 g/mol
In 44 g of CO2 there’s 1 mol of CO2
Then 1 g of CO2 there’s 1/44 mol of CO2
Therefore in 78.3 g of CO2 there’s — 1/44 x 78.3 =1.78 mol of CO2
4 0
3 years ago
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