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NARA [144]
3 years ago
14

Find an equation of the plane that is parallel to the xz-plane and is located 11 units to the right of the xz-plane in standard

perspective.
Mathematics
1 answer:
mina [271]3 years ago
8 0

Answer:

y = 11

Step-by-step explanation:

Since our plane is parallel to the xz plane, the x and z are independent of each other, i.e. they could be anything. So xz plane has an equation of y = 0. So if this plane is located 11 units to the right of the xz plane then its equation must be y = 11.

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Solve for r <br><br> 5-2(1-6r)=24
sammy [17]
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Solve each equation. Check your answer<br>r/238=8
ozzi
You have to get r by itself on one side. Multiply both sides by 238 to cancel it out of the denominator on the left side.

You are left with r = 8 × 238 or r = 1904.

To check, plug 1904 back into the equation.

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3 years ago
1. What are the coordinates of the circumcenter of a triangle with vertices A(0,1), B(2, 1) , and C(2, 5) ?
LenKa [72]
1. What are the coordinates of the circumcenter of a triangle with vertices A(0,1), B(2, 1) , and C(2, 5) ?

2. What are the coordinates of the centroid of a triangle with vertices A(−6, 0) , B(−4, 4) , and C(0, 2) ?

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3 years ago
Triangle ABC is defined by the points A(2,9), B(8,4), and C(-3,-2).
kotykmax [81]

Answer:

5y - 6x = 8 or y = 6x/5 + 8/5

Step-by-step explanation:

let M1= gradient of line AB and M2= gradient of the second line

When two lines are perpendicular, the product of their gradients is -1

i.e, M1M2= -1

M2= -1/M1

A(2,9) and B(8,4)

gradient= (y2-y1)/(x2-x1)

M1= (4-9)/(8-2)

= -5/6

M2= -1÷ -5/6

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5y+10=6x+18

5y= 6x + 8

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3 years ago
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