Question

What is the equation of this trend line? Enter your answers by filling in the boxes.

Answer 1

Answer:

the equation of this trend line is $K\:=\:-2J+28$

Step-by-step explanation:

Considering some of the points on the trend line

• (6, 16)  
• (4 20)  
• (2, 24)

As variable J represents x-axis, and variable K represents y-axis.

As the y-intercept can be obtained by putting x = 0.

So, when when x = 0, y = 28  

Thus, the y-intercept = 28  

As the slop intercept form is

$y\:=\:mx+b$

The slope can be obtained using the formula

$m=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

Taking any two points, let say

• (4 20)  
• (2, 24)

$m\:=\:\frac{20-24\:}{4-2}\:$  

$m=-\frac{4}{2}$

$m=-2$

The y-intercept = b = 28

As J represents the x-axis values, and K represents y-axis values

So, rewriting the slope intercept form

$y\:=\:mx+b$

$K\:=\:mJ+b$

$K\:=\:-2J+28$

Therefore, the equation of this trend line is $K\:=\:-2J+28$

Keywords: slope intercept form, point, graph

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