Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ =
≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM =
≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ
Well, If the area of ABC is 20cm², Then the area of ABS would be 10cm² and the area of ACS would also be 10cm². You basically are just cutting the ABC in half. I hope this helps!
Answer:
x = -2, 1/2
Step-by-step explanation:
Step 1: Isolate everything to 1 side
2x² + 3x - 2 = 0
Step 2: Factor
(2x - 1)(x + 2) = 0
Step 3: Find roots
2x - 1 = 0
2x = 1
x = 1/2
x + 2 = 0
x = -2
Answer:
So you go 3f×(5)=15fand then 15f×(2) =10f is your answer