I will be using the language C++. Given the problem specification, there are an large variety of solving the problem, ranging from simple addition, to more complicated bit testing and selection. But since the problem isn't exactly high performance or practical, I'll use simple addition. For a recursive function, you need to create a condition that will prevent further recursion, I'll use the condition of multiplying by 0. Also, you need to define what your recursion is.
To wit, consider the following math expression
f(m,k) = 0 if m = 0, otherwise f(m-1,k) + k
If you calculate f(0,k), you'll get 0 which is exactly what 0 * k is.
If you calculate f(1,k), you'll get 0 + k, which is exactly what 1 * k is.
So here's the function
int product(int m, int k)
{
if (m == 0) return 0;
return product(m-1,k) + k;
}
Hello,
++++++++++++++++++++++++
Answer C
++++++++++++++++++++++++
x^3+7^3=(x+7)(x²-7x+49) A: False (+14)
x^3+8^3=(x+8)(x²-8x+64) B:False (+8x)
x^3-10^3=(x-10)(x²+10x+100) D:False (-10x)
Answer: The mean of the data is 278.
Step-by-step explanation:
To the the mean of the data, we’ll have to add all the numbers up and divide it by the amount of data.
275+279+279+276+278+277+280+282+284+270=2780
2780/10=278
X=5
because 3 goes into 12 4 times and 20 divided by 4 equals 5
Answer:
Step-by-step explanation:
♨Rage♨
