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vovangra [49]
2 years ago
6

Find the variance for the following data set: 88, 40, 10, 52, 33, 55, and 86.

Mathematics
1 answer:
musickatia [10]2 years ago
7 0

Answer:

Variance s2 = 788.33333

Standard Deviation s = 28.077274

Count n = 7

Mean x¯¯¯ = 52

Sum of Squares SS = 4730

Step-by-step explanation:

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Solve the following quadratic equation for all values of x in simplest form.
Lynna [10]

Step-by-step explanation:

x = 2/5 or x = 0 Hope that will help

7 0
2 years ago
Trevor plans on buying a car. Four banks offer the annual interest rates shown.
mote1985 [20]

Solution

In order to find  greatest to least number, we have to convert the given fractions into decimals.

3 \frac{1}{10} % = 3 + 1/10 = 3 + 0.10 = 3.10%

3 \frac{2}{5}% = 3 + 2/5 = 3 + 0.40 = 3.40%

3 \frac{1}{4} %= 3 + 0.25 = 3.25%

3 \frac{1}{3}% = 3 + 0.33 = 3.33%

Now we can easily, compare the numbers and write from greatest to least.

3.40%, 3.33%, 3.25%, 3.10%

Greatest to least  = 3 2/5%, 3 1/3%3, 3 1/4%,  1/10%,

Thank you :)

8 0
3 years ago
Read 2 more answers
Cookies are being sold in the cafeteria to raise money for the cheerleaders. One giant cookie costs $1 while each one bought aft
sladkih [1.3K]

Answer:

y = 0.75x + 1

Step-by-step explanation:

Here, we want to write an equation in slope-intercept form to represent this information

Since $1 is the cost of 1 only, this represents our y intercept

It means if we are not interested in purchasing more than 1, our cost will be $1

Now, for each one bought after, we have a rate of $0.75 per one

Mathematically, that will be $0.75 times the number bought after

Hence. we have that;

y = 0.75x + 1

if 1, x = 0; so we have cost of 1 as $1

7 0
3 years ago
There are between 24 and 40 students in a class,
sergeinik [125]

Answer:answer is 387

Step-by-step explanation:ok got it

7 0
2 years ago
Read 2 more answers
A professor finds that the average SAT score among all students attending his college is 1150 ± 150 (μ ± σ). He polls his class
solniwko [45]

Answer:

Step-by-step explanation

Hello!

Be X: SAT scores of students attending college.

The population mean is μ= 1150 and the standard deviation σ= 150

The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.

If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:

H₀: μ = 1150

H₁: μ ≠ 1150

α: 0.05

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)

Z_{H_0}= \frac{1200-1150}{\frac{150}{\sqrt{25} } } = 1.67

The p-value for this test is  0.0949

Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.

I hope it helps!

7 0
3 years ago
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