What value of h makes the statement true? (17+h)+(–9) = 17+(5+(

The endpoints of CD are C(1, -6)and D(7,5). Find the coordinate of the midpoint, M

yuradex [85]

Answer:

(4, - 0.5 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ ]

Here (x₁, y₁ ) = C(1, - 6) and (x₂, y₂ ) = D(7, 5) , then

midpoint = ( $\frac{1+7}{2}$ , $\frac{-6+5}{2}$ ) = $\frac{8}{2}$ , $\frac{-1}{2}$ ) = (4, - 0.5 )

6 0

3 years ago

Round-Trip Cost ($) Departure City Atlanta Salt Lake City Cincinnati 340.1 570.1 New York 321.6 354.6 Chicago 291.6 465.6 Denver

Lemur [1.5K]

Answer:

$\bar x = 356.73$ ---Atlanta

$\bar x = 400.95$ --- Salt Lake City

Step-by-step explanation:

Given

The round trip flight data of Atlanta and Salt Lake City

Required

The mean price of both

Mean is calculated as:

$\bar x = \frac{\sum x}{n}$

For Atlanta

$\bar x = \frac{291.6 + 321.6 + 340.1 + 339.6 + 359.6 + 384.6 + 309.6 + 415.6 + 293.6 + 249.6 + 539.6 + 455.6 + 359.6 +333.9}{14}$

$\bar x = \frac{4994.2}{14}$

$\bar x = 356.73$

For Salt Lake City

$\bar x = \frac{570.1 + 354.6 + 465.6 + 219.6 + 311.6 + 297.6 + 471.6 + 618.4 + 513.6 + 523.2 + 381.6 + 159.6 + 267.6 + 458.6}{14}$

$\bar x = \frac{5613.3}{14}$

$\bar x = 400.95$

5 0

3 years ago

My teacher never taught us this so idk how to do it

Verdich [7]

${x}^{3} = 6\Leftrightarrow \sqrt[3]{ {x}^{3} } = \sqrt[3]{6} \Leftrightarrow x = \sqrt[3]{6}$

6 0

3 years ago

What are the roots of the polynomial equation x3 - 10x=-3x2+ 24? Please help

snow_tiger [21]

Answer:

x = -2, 3, -4.

Step-by-step explanation:

x^3 - 10x = -3x2 + 24 = 0

x^3 + 3x^2 - 10x - 24 = 0

The last term is 24 and the coefficient of x^3 is 1 so +/- 1, +-2, +/- 3 and +/- 4 could be among the roots ( by The Rational Root Theorem).

Let x = 1

f(x) = 1^3 +3(1)^2 - 10 - 24 = -30 so it's no t .

f(-1) = -1 + 3 + 10 - 24 = -12 so it's not -1.

Let x = 2:

f(2) = 2^3 +3*4 - 20 - 24 = -32 so its not 2

f(-2) = -8 + 12 + 20 - 24 = 0 so x = -2 is a root

and therefore x+ 2 is a factor and we divide:

x + 2 ) x^3 + 3x^2 - 10x - 24 ( x^2 + x - 12 <------ The quotient

x^3 + 2x^2

x^2 - 10x

x^2 + 2x

-12x - 24

..............

Now x^2 + x - 12 = (x - 3)(x + 4)

So (x + 2)(x - 3)(x + 4) = 0

This gives

x = -2, 3, -4.

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%

SVETLANKA909090 [29]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

$\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)$

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)$

The remaining elements of the product matrix are found in the same way.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)$

Simplify each element by multiplying the individual terms.

$\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)$

Now, sum each element of the matrix.

$\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}$

7 0

2 years ago

What value of h makes the statement true? (17+h)+(–9) = 17+(5+(–9))