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4 years ago

I NEED HELP (I’m sooo dumb lol)

Mathematics

1 answer:

statuscvo [17]4 years ago

7 0

To make a box and whisker plot, first you write down all of the numbers from least to greatest.

0, 1, 3, 4, 7, 8, 10

The median is 4, so that’s the middle line of the plot.

So now we have:
0, 1, 3, [4,] 7, 8, 10

So next we have to find the 1st and 3rd interquartiles..
0, [1,] 3, [4,] 7, [8,] 10

Those are the next 2 points you put on the plot.

Lastly, the upper and lower extremes. These are the highest and lowest numbers in the data.
[0,] 1, 3, 4, 7, 8, [10]

These are the final points on the plot.

To make the box of a box-and-whisker plot, you plot the 3 Medians of the data: 1, 4, and 8, and connect those to make a box that has a line in the middle at 4.

Next, you plot the upper and lower extremes: 0 and 10, by making “whiskers” that connect to the box. So you draw a line from the extremes to the box.

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Answer:

7,1/7

Step-by-step explanation:

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3 years ago

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Blizzard [7]

Answer:

$t=\frac{26.8-29.9}{\frac{2.7}{\sqrt{9}}}=-3.44$

$df=n-1=9-1=8$

$p_v =P(t_{(8)}$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and is not enough evidence to conclude that the claim is true.

Step-by-step explanation:

Data given

$\bar X=26.8$ represent the sample mean

$s=2.7$ represent the sample standard deviation

$n=9$ sample size

$\mu_o =29.9$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean exceed 29.9 or no, the system of hypothesis would be:

Null hypothesis: $\mu \geq 29.9$

Alternative hypothesis: $\mu < 29.9$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{26.8-29.9}{\frac{2.7}{\sqrt{9}}}=-3.44$

P-value

The degrees of freedom are given by:

$df=n-1=9-1=8$

Since is a one sided test the p value would be:

$p_v =P(t_{(8)}$

Conclusion

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and is not enough evidence to conclude that the claim is true.

6 0

4 years ago

Hi I need this asap if you also explain the work on how you got answers plz and thank you

weeeeeb [17]

Answer:

Q/ Draw a line ; Ans; 

$\frac{9}{5} —>1 \frac{4}{5}$