Answer:
1. f(x) = g(x - 4)
2. g(x) = f(x + 4)
3. y = (-3/2)x + 4
4. y = (-3/2)x - 2
Step-by-step explanation:
1. Notice that the point (0, -2) lies on g(x) and the point (4, -2) lies on f(x). That means the translation function from g(x) to f(x) is 4 units to the right. So, we have: f(x) = g(x - 4).
2. This one is kind of the opposite of number 1; g(x) is 4 units to the left of f(x), so we have: g(x) = f(x + 4).
3. Slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept. Slope is change in y over change in x, so pick any two points on the line of f: (0, 4) and (4, -2).
slope = m = (4 - (-2)) / (0 - 4) = 6/(-4) = -3/2
The y-intercept is where the graph crosses the y-axis, which is (0, 4), so b = 4. Then:
y = (-3/2)x + 4
4. Pick any two points to find the slope: (-4, 4) and (0, -2).
slope = m = (4 - (-2)) / (-4 - 0) = 6/(-4) = -3/2
The y-intercept is at (0, -2), so b = -2. Then:
y = (-3/2)x - 2
Answer:
- one negative real root in [-5, -4]; two complex roots
- the complex roots cannot be isolated in the same way.
Step-by-step explanation:
A graphing calculator is a wonderful tool for this. It shows the one real root to be near -4.062, so between -5 and -4.
The value of the cubic at x = -5 is -315; at -4 it is +15, so the root is definitely between those values.
The one real root is isolated to being between (-5, -315) and (-4, 15). The complex roots are not isolated.
Note that (5π)/6 radians = 150°. Therefore the given angle is in quadrant 2.
Refer to the figure shown below.
Reference angles are measured relative to the horizontal axis.
Therefore the reference angle in each quadrant is π/6 radians or 30°.
Denote the reference angle as θ'.
Then, in quadrant 1,
cos θ' = √3/2, sin θ' = 1/2, tan θ' = √3.
Because we are in quadrant 2,
sin θ' = π/6;
sin(5π/6) is positive, but cos (5π/6) and tan (5π/6) are negative.
Answer:
5π/6 is in quadrant 2.
The reference angle, θ' = π/6.
sin(5π/6) is positive, cosine and tangent are negative.