<span>Vertical farming is the exercise of creating foodstuff and medication in sheer laden layers, vertically inclined exteriors and/or combined in other structures. The modern thoughts of vertical farming use indoor farming methods and controlled-environment agriculture (CEA) technology, where all environmental issues can be well-ordered. So knowing all of this, the negative outcome would be D.</span>
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Answer:
Option (D) i.e., s1.getClassRank( ); is the correct option to the following question.
Explanation:
Here, in the following option, the object "S1" is the object of the class "rank" and "getClassRank( )" is the function of that class "rank". so, in the following code the function "getClassRank( )" is called through the class object which computes and returns the class rank of the students.
So, that's why the following option is the correct way to call the function.
Answer:
The program is as follows:
<em>5 INPUT A,B</em>
<em>6 PROD = A * B</em>
<em>7 PRINT PROD</em>
<em>8 TOTAL = A + B</em>
<em>9 PRINT TOTAL</em>
<em>10 DIFF = A - B</em>
<em>11 PRINT DIFF</em>
<em>12 END</em>
Explanation:
This gets input for the two numbers
<em>5 INPUT A,B</em>
This calculates the product
<em>6 PROD = A * B</em>
This prints the calculated product
<em>7 PRINT PROD</em>
This calculates the sum
<em>8 TOTAL = A + B</em>
This prints the calculated sum
<em>9 PRINT TOTAL</em>
This calculates the difference
<em>10 DIFF = A - B</em>
This prints the calculated difference
<em>11 PRINT DIFF</em>
This ends the program
<em>12 END</em>
Answer:
double the bandwidth assigned per channel to 40 MHz
Explanation:
The best way of doing this would be to double the bandwidth assigned per channel to 40 MHz. This will make sure that the capacity is more than sufficient. This is simply because the bandwidth of a channel represents how much information can pass through the channel at any given second, the larger the channel, the more information/data that can pass at the same time. Therefore, if 20 MHz is enough for the network, then doubling this bandwidth channel size would be more than sufficient capacity for the network to handle all of the data.
