Answer:
The program to calculate factor can be given as:
Program:
#include <stdio.h> //include header file
int main() //defining main function
{
int a,i; //defining integer variable
printf("Enter any number: "); //print message
scanf("%d",&a); //input value from user end
for(i=1;i<=a;i++) //loop for calculate factor values
{
if(a%i==0) //define condition for factor
{
printf("%d\n",i); //print values
}
}
return 0;
}
Output:
Enter any number: 15
1
3
5
15
Explanation:
In the above C language program the header file is include that provide the use of basic function, in the next line the main method is defined, inside this method two integer variable "a and i" is defined in which variable a is used to take value from user end and variable i is used in loop and conditional statement.
- In the next step, for loop is declare, that start from 1 and end with value of variable a, inside a loop, if block is used that checks (a%i==0), in this if variable i value modeler value equal to 0.
- The loop will use the print function that prints variable "i" element in a new line, which is the factor the values.
Cause weak ones aren't that strong and can easily break, but a strong connection will last longer and will be harder to break. For example you need to build a connection with your dog or else your dog wont trust you. Basically building a strong connection always you to build the trust stronger.... I think this is the answer you are looking for depending on what connection you are looking for
<u>Explanation:</u>
Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:
// C++ program to count even digits in a given number .
#include <iostream>
using namespace std;
// Function to count digits
int countEven(int n)
{
int even_count = 0;
while (n > 0)
{
int rem = n % 10;
if (rem % 2 == 0)
even_count++;
n = n / 10;
}
cout << "Even count : "
<< even_count;
if (even_count % 2 == 0 )
return 1;
else
return 0;
}
// Driver Code
int main()
{
int n;
std::cin >>n;
int t = countEven(n);
return 0;
}
Change the line in word, it basically returns
