Answer: pi/8
Step-by-step explanation:
adding or multiplying an irrational by a rational will result in another irrational. So we could take something like pi and divide it until it’s between 2/7 and 3/7. I did that and apparently pi/8 works, so boom
Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=
1) 2x+4y=10
3x+5y=14 .
find d2, dx2, and dy
2) Solve the system of equations algebraically and show your work.
2x + 3y = 12
2x - y = 4
3) Which of the ordered pairs (5,5),(5,0) and (-3,2) can be found in the shaded solution area for the system of inequalities below? (The ordered pair must be in the double shaded region or it is not a solution of the system.)
x+2y<6
2x+y > or equal too 9 so yea hoped this helped
Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.
Because we know 3 and -1 (multiplicity 2) are both roots, the last root
is such that we can write

There are a few ways we can go about finding
, but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be
.
Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have

so the missing root is 3.
Other things we could have tried that spring to mind:
- three rounds of division, dividing the quartic polynomial by
, then by
twice, and noting that the remainder upon each division should be 0
- rational root theorem