Answer:
An interest rate is the amount of interest due per period, as a proportion of the amount lent, deposited or borrowed. The total interest on an amount lent or borrowed depends on the principal sum, the interest rate, the compounding frequency, and the length of time over which it is lent, deposited or borrowed.
Answer:
the answer would be D because meadian is what in the middle
Answer:
1. 14/15
2. 5 7/8
3. 81.25%
Step-by-step explanation:
1. (fraction) 7/9 divided by 5/6 (fraction)
7/9 ÷ 5/6 =
= 7/9 * 6/5
= (7 * 6)/(9 * 5)
= 42/45
= 14/15
2.
1 3/8 + 4 1/2 =
= 1 + 3/8 + 4 + 1/2
= 1 + 4 + 3/8 + 4/8
= 5 + 7/8
= 5 7/8
3.
percent = part divide by whole times 100
13/16 * 100 =
= 81.25%
Answer:
84 seconds
Step-by-step explanation:
Because if you divide all of that you would get that answer
Answer: 195.5 or 12 7/32
Step-by-step explanation:
There is no letter tetha in the table so I use α instead. However it is not sence to final result.
The expression is:
(sinα+cosα)/(cosα*(1-cosα))
Lets divide the nominator and denominator by cosα
(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=
=(8/15+1)/(1-cosα)= 23/(15*(1-cosα)) (1)
As known cos²α=1-sin²α (divide by cos²α both sides of equation)
cos²a/cos²α=1/cos²α-sin²α/cos²α
1=1/cos²α-tg²α
1/cos²α=1+tg²α
cos²α=1/(1+tg²α)
cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=
=+-sqrt(225/289)=+-15/17 (2)
Substitute in (1) cosα by (2):
1st use cosα=15/17
1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5
2-nd use cosα=-15/17
2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32
