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Illusion [34]
4 years ago
5

Which of the following sets of driver's actions are multi-task performances necessary for the safe vehicle operation?a. Signalin

g; Changing Gears ;Checking mirrorsb. Signaling; Brakes ;Checking mirrorsc. Signaling; Changing Gears ; Door opening
Physics
1 answer:
quester [9]4 years ago
8 0

The sets of driver's actions “Signalling; Changing Gears; Checking mirrors” are multi-task performances necessary for the safe vehicle operation.

Answer: Option A

<u>Explanation:</u>

Signaling is what drivers plan to do is important for security because other drivers can only know if he tells them. Here are some general rules about Signalling or turns.

  • Signal early: Signal well before turning back is the best way to prevent others from trying to get through you.
  • Continuous signal: To turn safely, the driver must have both hands on the steering wheel. He should not stop the signal until he completed the turn.
  • Cancel the alarm: The driver should remember to turn off signaling after completing his turn (if you have no attenuation signals).

The correct gear change is important. If he can't put the vehicle in the right gear while driving, he has less control. And also, he must check the exterior mirrors on both sides regularly. He needs to check his vehicle mirrors to make sure nobody stands or walks past him.

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A car has a distance between axles of 6.2 m and a center of mass located 2.2 m from the front axle. What is the
NARA [144]

Answer:

The correct option is  C

Explanation:

From the question we are told that

    The distance between axles of the car  is  d_a  =  6.2

     The position of the car's center of mass is  D  = 2.2 \ m  \ in \ front \  of  \  the \  axel

Now  we can evaluate the distance of the center of mass to the rear axle as follows

        k  =  d_a  -  D

substituting values

      k  =  6.2 -  2.2

      k  = 4 \ m

assuming the car is   at equilibrium,  taking moment about the center of mass

          W_{front \  axle} *  D  -  W_{rear \  axle} *  k  = 0

=>        W_{front \  axle} *  D     =  W_{rear \  axle} *  k

=>       \frac{W_{front \  axle}}{W_{rear \  axle} }       =    \frac{k}{D}

substituting values

             \frac{W_{front \  axle}}{W_{rear \  axle} }       =    \frac{4}{2.2}

           \frac{W_{front \  axle}}{W_{rear \  axle} }       =    1.81       Note [W_{front \  axle} is the front axle weight  and  

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Answer:

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Explanation:

Momentum is defined as:

p=mv

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For the object in this problem, we know:

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m = 50 kg is the mass

Solving for the velocity, we find:

v=\frac{p}{m}=\frac{200}{50}=4 m/s

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