Complete Question
A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutions. At what rate is the flywheel spinning when the power comes back on(in rpm)? How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?
Answer:
Explanation:
From the question we are told that:
Angular velocity
Mass
Diameter d
Off Time
Oscillation at Power off
Generally the equation for Angular displacement is mathematically given by
Generally the equation for Time to come to rest is mathematically given by
Therefore Angular displacement is
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Answer:
Explanation:
The law of gravitation has to be used in this question along with Newton's second law
Velocity = distance/time
v = (35)/(1/2)
v = 70 km/h
60 km/h for 25 minutes
25 minutes = 25/60 hour
distance= velocity * time
d =(60) * (25/60)
d = 25 km
ΔV = { V(initial) - V(final) } / time
v= (70-60) / (45/60)
average velocity = 13.33 km/h
avg veloticy = 3.7 m/s
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Explanation:
The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically, it is given by :
...............(1)
Where m₁ and m₂ are masses
r is the distance between them
It is clear from equation (1) that :
1. The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.
2. The gravitational force between two objects is proportional to the product of the masses of the two objects.
Hence, this is the required solution.