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3 years ago

An object experiences an impulse, moves and attains a momentum of 200 kg·m/s. If its mass is 50 kg, what is its velocity?

Physics

1 answer:

Nady [450]3 years ago

8 0

Answer:

4 m/s

Explanation:

Momentum is defined as:

$p=mv$

where

m is the mass of the object

v is its velocity

For the object in this problem, we know:

p = 200 kg m/s is the momentum

m = 50 kg is the mass

Solving for the velocity, we find:

$v=\frac{p}{m}=\frac{200}{50}=4 m/s$

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A load of mass 5kg is raised through a height of 2m. (g=10mls)

s2008m [1.1K]

The gain in gravitational potential energy of the mass = 100 kg m^2 / s^2.

<u>Explanation:</u>

Gravitational potential energy is an energy in which an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the Earth's surface where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.

The formula for the gravitational potential energy is the product of mass, gravity, and height.

GPE = m *g *h

where m represents mass in kg,

g represents the gravity,

h represents the height.

GPE = 5 * 10 * 2 = 100 kg m^2 / s^2.

7 0

3 years ago

All digits shown on measuring device, plus one estimated digit, are considered_______.

vichka [17]

Significant

Explanation:

All the digits shown on a measuring device and one estimated digit are all considered to be significant.

A significant digit is a set of values that shows how precise a measurement is reported.

Measuring devices such as calculators gives their values in significant digits.

Non- zero digits in a measurement are always significant.
Zero's before a decimal are not significant. Those after a number in a decimal are significant.
Zero's between digits are significant.

learn more:

Significant digits brainly.com/question/2743055

#learnwithBrainly

3 0

3 years ago

Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak

Mashutka [201]

Answer:

Part a)

$\Delta \phi = 2.2 \pi$

Part b)

$f = 411.3 Hz$

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

$\Delta x = 3\sqrt2 - 3$

$\Delta x = 1.24 m$

now phase difference is related with path difference as

$\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)$

$\Delta \phi = \frac{2\pi}{\lambda}(1.24)$

here in order to find the wavelength

$\lambda = \frac{c}{f}$

$\lambda = \frac{340}{300} = 1.13$

now we have

$\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi$

Part b)

Now we know that when phase difference is odd multiple of $\pi$

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

$\Delta \phi = 3\pi$

so we have

$3\pi = \frac{2\pi}{\lambda}(1.24)$

so we have

$\lambda = 0.827$

now we have

$\frac{340}{f} = 0.827$

$f = 411.3 Hz$

4 0

3 years ago

A basketball player jumps straight upward. After 0,625 s, she is 0.441 m above the ground. What is her initial velocity?????????

Lunna [17]

Answer:

v₀ = 3.77 [m/s]

Explanation:

This problem can be solved in a simple way by means of the following equation of kinematics.

$y=y_{o}+v_{o}*t+\frac{1}{2}*g*t^{2}$

where:

y - yo = 0.441 [m]

Vo = initial velocity [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 0.625 [s]

$0.441 = v_{o}*(0.625)-\frac{1}{2} *9.81*(0.625)^{2} \\2.357 = v_{o}*0.625\\v_{o}=3.77[m/s]$

Note: The sign of the acceleration is negative since the movement of the basketball player is against of the gravity acceleration.

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3 years ago

Why is boiling water considered a physical change?

Liono4ka [1.6K]

Answer:

Boiling water is an example of a physical change and not a chemical change because the water vapor still has the same molecular structure as liquid water.

(credits to lumenlearning)

Explanation:

7 0

3 years ago

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