MaCa∆Tb = MbC∆Tb
Where
m is the mass of a compound
<span>
C
is the specific heat of a compound
</span>∆T is the change of temperature of the compound
<span>
(0.502
kg water)(4180 j/kg C)( 28.6 – 22 C) = ( 0.145 kg tungsten) ( C ) ( 130 – 28.6
C)
</span>Solve
for C
<span>C
= 941.9 J /kg C </span>
<span>a) M is the big one
m is the little one
v is the speed of each of them when they impact
V = speed of mii after collision
Conservation of momentum
Mv – mv = mV
Conservation of energy
1/2Mv^2 + 1/2mv^2 = 1/2 mV^2
This pair simplify to give
M = 3m
V = 2v
So m = 0.21kg
and h = 4 . 2.7 = 10.8 m</span>Source(s):<span>Old teacher</span>
Answer:
1.0125 x 10^19
Explanation:
current flowing through conductive wire= 9mA = 9 x 10^ -3 A
charge passing per 3 min
Q = It
= 9 x 10^ -3 x (3 x 60)
= 1.620 C
no of electrons in charge
Q = ne
1.620 = n x 1.6 x 10 ^ -19
n. = 1.0125 x 10 ^19
