Question

Sue's average score for three bowling games was 162. In the second game, Sue scored 10 less than in the first game. In the third game, she scored 13 less than in the second game. What was her score in the first game?

Answer 1

Answer:

Her score in the first game was 173.

Step-by-step explanation:

Sue's total score for the 3 games = 3*162 = 486 points.

Let her score in the first game be x points. Then in the second game she scored (x - 10)  and in the third, ( x - 10 - 13) points:

x + (x - 10) + (x - 23) = 486

3x - 33 = 486

3x = 519

x = 173 (answer).

Answer 2

Answer:

173

Step-by-step explanation:

Assuming x to be Sue's score in the first game, the score in her second game would be (x-10) and (x-10-13).

Also, we know that the average score for these three bowling games was 162 so we can write:

$\frac {(x) + (x-10) + (x - 10 - 23)}{3} =162$

$\frac{x+x-10+x-23}{3} =162$

$\frac{3x-33}{3} =162$

$3x-33=162*3$

$3x=486+33$

$3x=519$

$x=\frac{519}{3}$

Therefore, Sue scored 173 in her first game.