For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
If this is in science terms its a plain if this is in mathematical terms, the answer is the number 0 anything below is negative, anything abouve is pos
Answer:
(x + 2)² + (y + 9)² = 49
Step-by-step explanation:
Equation:
(x - h)² + (y - k)² = r²
(x - -2)² + (y - -9)² = 7²
(x + 2)² + (y + 9)² = 49
Answer:
not sure if this is a right answer. but hope this helps
Step-by-step explanation:
Answer:
Step-by-step explanation:
Step 1: Convert into improper fractions
Step 2: Find least common denominator and find equivalent fractions
Step 3 : Do the required operation
Least common denominator of 2 , 4 = 4
