a) Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of equations
b) since the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of equation
In order to show if the given point corresponds to the given function, we will have to substitute the value of x into the function to see if we will have its corresponding y-value
For the point (-0.8, -0.6), substitute x = -0.8 into both functions as shown:
f(x) = 2x + 1
f(-0.8) = 2(-0.8) + 1
f(-0.8) = -1.6 + 1
f(-0.8) = -0.6
Simiarly;
y = -3(-0.8)- 3
y = 2.4 - 3
y = -0.6
Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of equations
For the point (1/3, 2), substitute x = 1/3 into both functions as shown:
x = (y+2)/2
x = (2+2)/2
x = 4/2
x = 2
Simiarly;
x + 2 = 3
x = 3-2
x = 1
Since the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of equations
Learn more on systems of equation here: brainly.com/question/847634
48 mm long
Since a square has all equal sides, it will be 12mm for all sides
Perimeter = L (Length) + W (Width) + L + W
(In this case since it’s a 2D shape)
12 + 12 + 12 + 12 = 48
Hope this helped :)
longer congruent sides = 6-0 OR 4-(-2) = 6units
perimeter= 3.6×2 + 6×2 = 19.2units
height of parallelogram= 2-(-1) = 3 units
area= 3×6 = 18unit^2
It depends on your computer. If your computer lags easily, I suggest writing a few docs.
Using the product rule, which states that (uv)' = u'v + uv':
If y = (e^-2x)(sec3x)
y' = (e^-2x)'(sec3x) + (e^-2x)(sec3x)'
y' = -2(e^-2x)(sec3x) + (e^-2x)(3 sec3x tan3x)
y' = 3(e^-2x)(sec3x tan3x) -2e^-2x (sec3x)
This matches choice B.
