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3 years ago

What is the number of pie multiplied by two

Mathematics

2 answers:

Amanda [17]3 years ago

8 0

Pie goes on forever, so you round it to 3.14.
3.14*2= 6.28
Hope that helped!

saveliy_v [14]3 years ago

6 0

Pie is a infinite number. Most times you just use 3.142 as pie. So you do 3.142x2. But i recommend you using a calculator and pressing the pie button. It will give you a lot accurate answer...

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How many terms are in the expression? 9a + 6b + 3c + 1 A) 1 B) 2 C) 3 D) 4

Kaylis [27]

Answer:

D.) there is 9a and 6b ,3c and 1 thats four different terms

Step-by-step explanation:

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2 years ago

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3 years ago

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18.4b=44.16 need help fast

MaRussiya [10]

Answer:

If it's 18.4b=44.16: $b=2.4$

If it's 4b=44.16: $b=11.04$

Step-by-step explanation:

If it's 18.4b=44.16:

$18.4b=44.16\\\\\frac{b}{18.4}=\frac{44.16}{18.4}\\\\b=2.4$

If it's 4b=44.16:

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3 years ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

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Mademuasel [1]

Answer:

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