2 years ago

Tres compañías de navegación pasan por cierto puerto. La primera cada 8 días; la

Mathematics

1 answer:

lilavasa [31]2 years ago

4 0

I think this is a least common multiple question

So they would all arrive on day 504, (which probably is a few years)

8 = 2 × 2 × 2

18 = 2 × 3 × 3

21 = 3 × 7

I might be right I might be wrong, IM not positively sure but yknow

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The amount of time needed for a certain machine to process a job is a random variable with mean EXi = 10 minutes and Var(Xi)=2 m

lana66690 [7]

Answer:

0.98732

Step-by-step explanation:

Given that :

Mean = 10 minutes

Variance = 2 minutes

For less than equal 40 jobs

Mean (m) = 40 * 10 = 400 minutes

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Standard deviation (s) = √variance = √80

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