I’m thinking A. Would be the most suitable answer for this one
No matter the number of times you rolled the dice, the probability of getting a number is always 1/6. But here we can choose 4 numbers ( 1 to 4) hence the probability P( 1 or 2 or 3 or 4) = 4/6 2/3 = 0.6667 = 66.67% (A)
Answer:
25 cm
Step-by-step explanation:
a^2 + b^2 = c^2
7^2 + 24^2 = c^2
49 + 576 = c^2
c^2 = 625
c = 25
Answer: 25 cm
From the given figure, it can be seen that 13x = 15x - 8 because they are vertical angles and thus are equal.
13x = 15x - 8
15x - 13x = 8
2x = 8
x = 8/2 = 4
Thus, 15x - 8 = 15(4) - 8 = 60 - 8 = 52.
RT is a diameter, which means that mRT = 180
mRV + mVU + 52 = 180
mRV + mVU = 180 - 52 = 128
Now, given that mRV = mVU,
Thus, 2mVU = 128
Therefore, mVU = 128 / 2 = 64°
The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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