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Ber [7]
2 years ago
15

I will give brainliest

Mathematics
2 answers:
avanturin [10]2 years ago
6 0
4m because it looks like 1/3 of 12m and 12 divided by 3 is 4. Hope it’s correct, I deeply apologize if its wrong.
lisabon 2012 [21]2 years ago
3 0

Answer:

4 m because I put it on procreate and put tics on the 12 m to see how much each m was and measured x with that

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When the fraction below is written as a repeating decimal, which digits are repeating?
kaheart [24]
A, 63. If you put in into the calculator, you divide 7 by 11 and you get an answer with a repeating decimal of 6 and 3.
8 0
3 years ago
How to solve these 3 problems
Bingel [31]

Answer:

  1. a. decay; b. growth; c. decay; d. neither
  2. r = 4; a = 1; y = 1·4^x
  3. a. an = 3(5^(n-1)); b. f(x) = (3/5)(5^x); c. exponential growth; d. y-intercept: 3/5; first term: 3.

Step-by-step explanation:

There are two kinds of exponential problems here.

  1. exponential functions of the form f(x) = a·b^x
  2. exponential sequences of the explicit form an = a1·r^(n-1)

The second problem gives you a table that suggests the sequence form, but it asks for the exponential function form. The third problem does something similar.

__

<h3>1.</h3>

In an exponential function of the form f(x) = a·b^x, the function grows if b>1 and decays if b<1. Using this check, we can easily answer ...

  a. 0.4 < 1 . . . decay

  b. 1.3 > 1 . . . growth

  c. 1/2 < 1 . . . decay

  d. 1 = 1 . . . neither growth nor decay; the function is constant: j(x) = 1.

__

<h3>2.</h3>

The value of x is given starting at 1, so we can consider this a geometric sequence. The common ratio is r = 16/4 = 4. The first term is a1 = 4, so the explicit formula for the sequence is ...

  an = 4·4^(n-1)

When this is expanded to get rid of the constant in the exponent, we have ...

  an = 4·(4^n)·(4^-1) = 1·4^n

We recognize this form as matching the functional form f(x) = a·r^x. The multiplier of the exponential factor is a=1. In summary, ...

  r = 4; a = 1; f(x) = 1·4^x

__

<h3>3.</h3>

The first term of this geometric sequence is a1 = 3. The common ratio is r = 15/3 = 5. Using the explicit formula, we have ...

 a. explicit form: an = 3·5^(n-1)

Using the method of question 2 to write the functional form, we find ...

  an = 3(5^n)(5^-1) = (3/5)(5^n)

  b. functional form: f(x) = (3/5)(5^x)

  c. function family: exponential growth functions

 d. y-intercept: (3/5) . . . . read this from the f(x) form

     1st term: the first term listed in the given sequence is 3

_____

<em>Additional comment</em>

The "y-intercept" of a sequence is irrelevant (undefined), as the sequence term numbering starts with 1, not 0. The domain of the explicit formula is <em>natural numbers</em>, which does not include 0.

Similarly, the "first term" of a function f(x) needs further definition. Here, we've answered the question by saying the first term is f(1). There is no conventional definition of a "first term" for a continuous function.

3 0
2 years ago
Claudia owns a wood house in the country worth $75,000, and the contents
irina [24]

Answer: D $852.00

Step-by-step explanation:

4 0
3 years ago
Graph the image of this figure after a dilation with a scale factor of 1/2 centered at the origin.
Nataly_w [17]

Answer:

In stead of 2,2 the point would be 1,1. Instead of -4,4 it would be -2,2 and instead of 6,8 it would be 3,4.

Step-by-step explanation:


4 0
3 years ago
Find the equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0)
Elenna [48]

The equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0) is y=x^{2}-x-12

<h3><u>Solution:</u></h3>

We have to find the equation of a parabola that opens up and has the following x intercepts (-3, 0) and (4, 0)

x-intercepts of the parabola are (−3, 0) and (4, 0)

So, we can form an equation:

Also x = 4

x – 4 = 0

x – 4 = 0 is another factor of quadratic equation.

The quadratic function is:

\begin{array}{l}{y=(x+3)(x-4)} \\\\ {y=x^{2}-4 x+3 x-12} \\\\ {y=x^{2}-x-12}\end{array}

Hence, the equation of the parabola is  y=x^{2}-x-12

5 0
3 years ago
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