32.0 you just add the first and last numbers then muptily the middle number by you anwser and divdie your 2 anwsers to gether
-x - y = 8
2x - y = -1
Ok, we are going to solve this in 2 parts. First we have to solve for one of the variables in one of the equation in terms of the other variable. I like to take the easiest equation first and try to avoid fractions, so let's use the first equation and solve for x.
-x - y = 8 add y to each side
-x = 8 + y divide by -1
x = -8 - y
So now we have a value for x in terms of y that we can use to substitute into the other equation. In the other equation we are going to put -8 - y in place of the x.
2x - y = -1
2(-8 - y) - y = -1 multiply the 2 through the parentheses
-16 - 2y - y = -1 combine like terms
-16 - 3y = -1 add 16 to both sides
-3y = 15 divide each side by -3
y = -5
Now we have a value for y. We need to plug it into either of the original equations then solve for x. I usually choose the most simple equation.
-x - y = 8
-x - (-5) = 8 multiply -1 through the parentheses
-x + 5 = 8 subtract 5 from each side
-x = 3 divide each side by -1
x = -3
So our solution set is
(-3, -5)
That is the point on the grid where the 2 equations are equal, so that is the place where they intersect.
Answer: b
Explanation:
The line of best fit to a scattergram is obtained in linear regression analysis by minimizing the sum of the squared errors.
For example, in the diagram shown below, there are n data points in the scattergram.
The error for the i-th data point is
.
The coefficients (a and b) for the line of best fit are determined using calculus, to minimize
.
For the function y = 7x - 1, if you state that the domain(or all the numbers you can substitute in for "x") of that function is the set of all real numbers, then you can assume that there will be an infinite number of solutions for the function.
In other words, if you substitute any real number in for "x" you will find that you will get a corresponding value for "y". In fact, these "pairs" of corresponding values of x and y are called ordered pairs and represent the various solutions of the equation.
Your response should be choice D:
