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3 years ago

URGENT DUE TODAY!!! PLEASE HELP!!! i will give brainliest

Mathematics

1 answer:

rewona [7]3 years ago

4 0

Answer:

180 centimeters

Step-by-step explanation:

First, you have to make these into 2 different shapes. Two different prisms. You can see all the dimensions on the right shape, but not the left. How do you know the width? Well, since the width is the same for the WHOLE figure, the width for both shapes is the same. To find the volume of a rectangular prism, you need to multiply the length, width, and height.

Length * height * width

Shape 1: $8 * 3 * 5 = 120$ cm

Shape 2: $2*6*5=60$ cm

Then, you add the volumes of the 2 shapes to get the final volume.

120 + 60 = 180 cm

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Solve (x + 3)2 + (x + 3) – 2 = 0. Let u = Rewrite the equation in terms of u. (u2 + 3) + u – 2 = 0 u2 + u – 2 = 0 (u2 + 9) + u –

Verdich [7]

Answer:

The solutions of the original equation are x=-5 and x=-2

Step-by-step explanation:

we have

$(x+3)^2+(x+3)-2=0$

Let

$u=(x+3)$

Rewrite the equation

$(u)^2+(u)-2=0$

Complete the square

$u^2+u=2$

$u^2+u+1/4=2+1/4$

$u^2+u+1/4=9/4$

rewrite as perfect squares

$(u+1/2)^2=9/4$

square root both sides

$(u+1/2)=\pm\frac{3}{2}$

$u=(-1/2)\pm\frac{3}{2}$

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$u=(-1/2)-\frac{3}{2}=-2$

the solutions are

u=-2,u=1

Alternative Method

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$(u)^2+(u)-2=0$

$a=1\\b=1\\c=-2$

substitute in the formula

$u=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$u=\frac{-1\pm\sqrt{9}} {2}$

$u=\frac{-1\pm3} {2}$

$u=\frac{-1+3} {2}=1$

$u=\frac{-1-3} {2}=-2$

the solutions are

u=-2,u=1

Find the solutions of the original equation

For u=-2

$-2=(x+3)$ ----> $x=-2-3=-5$

For u=1

$1=(x+3)$ ----> $x=1-3=-2$

therefore

The solutions of the original equation are

x=-5 and x=-2

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3 years ago

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Did I do this right?

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Yep! You did it correct :)

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