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Sonbull [250]
4 years ago
5

Compound A melts at 220.5-222.1 degrees C and compound B melts at 221.2 - 223.4 degrees C. When mixed together, the mixture of A

and B melts at 216.4 - 224.6 degrees C. Are compounds A and B the same compound? Explain.
Chemistry
1 answer:
Viefleur [7K]4 years ago
8 0

Answer:

NO, they are not the same compound

Explanation:

Given that;

Compound A melts at  220.5 °C - 222.1 °C;      &

Compound B melts at   221.2 °C - 223.4 °C

It is seen from above that there is little difference in the melting point of Compound A and B. This little difference can be as a result of factors associated when carrying the melting process or because different methods were employed in the establishing their melting points.

Also, we were told that when they were both mixed together ,  the mixture of compound A and B melts at 216.4 °C  - 224.6 °C.

This statement has largely indicated that both compounds are not the same at all, because if they were, the mixture of compound A and B melting point must be identical to one of the individual compound's melting point either from compound A or from compound B.

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If you have 3.54 g of H2, how many grams of NH3 can be produced?
morpeh [17]
3.54g H2 means you have 3.54 / 2  = 1.77 moles of H2, which means you have 1.77*2 = 3.54 moles of H atom.

Since 1 mole of NH3 has 3 moles of H, so you can produce 3.54 / 3 moles of NH3, which is (3.54/3) * (12+3) = 17.7 grams
5 0
3 years ago
Calculate ΔHrxn for the following reaction: Fe₂O₃(s)+3CO(g)→2Fe(s)+3CO₂(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/
ExtremeBDS [4]

Answer : The enthalpy change of reaction is -23.9 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given final reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) 2Fe(s)+\frac{3}{2}O_2(g)\rightarrow Fe_2O_3(s)    \Delta H^o_1=-824.2kJ

(2) CO(g)+\frac{1}{2}O_2(g)\rightarrow CO_2(g)    \Delta H^o_2=-282.7kJ

First we will reverse the reaction 1 and multiply equation 2 by 3 then adding both the equation, we get :

(1) Fe_2O_3(s)\rightarrow 2Fe(s)+\frac{3}{2}O_2(g)    \Delta H^o_1=+824.2kJ

(2) 3CO(g)+\frac{3}{2}O_2(g)\rightarrow 3CO_2(g)    \Delta H^o_2=3\times (-282.7kJ)=-848.1kJ

The expression for final enthalpy is,

\Delta H=\Delta H^o_1+\Delta H^o_2

\Delta H=(+824.2kJ)+(-848.1kJ)

\Delta H=-23.9kJ

Therefore, the enthalpy change of reaction is -23.9 kJ

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Answer:

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Explanation:

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