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LUCKY_DIMON [66]
3 years ago
9

8 billion molecules of O2 gas

Chemistry
1 answer:
bixtya [17]3 years ago
6 0
What do u want to solve?
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What is the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol)?
NemiM [27]

the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g

The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn

3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2

the formula is n= mass/M so, now substituting values

m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3

so, by substituting values, 2 X101.96 X1.74g / 3 X 86.94 =1.36g

so mass of aluminum oxide obtained = 1.36g

To learn more about Mass:

brainly.com/question/19694949

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2 years ago
jamie is not sure a new medication will work because it has not had a large test group. Is jamie being creative?
Georgia [21]

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3 years ago
Convert 345 g to kilograms (kg).<br> 1 kg = 1000 g<br> (please show work) ASAP
astraxan [27]

Answer:

345 converted to kilograms is 0.345

Explanation:

345 divided by 1000 is 0.345

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