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LUCKY_DIMON [66]
3 years ago
9

8 billion molecules of O2 gas

Chemistry
1 answer:
bixtya [17]3 years ago
6 0
What do u want to solve?
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Use the helium-4 isotope to define atomic number and mass number. why does knowledge of atomic number enable us to deduce the nu
Nuetrik [128]
Helium - 4 isotope has 2 protons and 2 neutrons.

Its atomic number is 2 (the number of protons). Atomic number is the number of protons in the atom of an element and it identifies the element. All the isotopes of an element have the same atomic number (same number of protons). So, all the isotopes of hellium have 2 protons.

The number 4 that identifies the helium - 4 isotope is the mass number, i.e. the number of protons plus the number of neutron. So, helium-4 isotope has 2 protons and 2 neutrons. While, other isotopes of helium have 2 protons but different number of neutrons.

The atomic number enable us to deduce the number of electrons in an atom because the atoms are neutral, which implies that the positive and negative charge are equal. Given that the magnitude of the charge of electons and protons are equal but the sign is opposed (protons are positve and electrons are negative) the number of electrons in the atom equals the number of protonts. That is why the atomic number is also the number of electrons of the atom.
8 0
3 years ago
What is the general trend in electro negativity as you move from left to right across the periodic table
viva [34]

Answer:

On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you go down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.

Explanation:

6 0
3 years ago
Calculate the number of atoms per unit cell in each type of cubic unit cell. Enter three integers separated by commas (e.g., 1,2
agasfer [191]

Answer:

1, 2, 4

Explanation:

The primitive cubic unit cell has eight corners, and each corner is shared with 8 cubic unit cells. Therefore since we have one atom at each corner, we will have:

8 corner x  1 atom/8 corner = 1 atom

There is then the equivalent of one atom per unit cell in the primitive cubic cell.

For the body-centered cubic unit cell, we have 8 corners again shared each by 8 lattices as in the simple cubic plus we have one atom  in the center of the cubic lattice. Therefore, the number of atoms in the body -centerd unit cell is two:

8 corner x 1 atom/8 corner = 1 atom

                      +

1 atom in the center

= 2 atoms/ unit cel

For the face-centerd cubic again we have 8 atoms in the corners shared by 8 lattices, plus 1 atom in each of the faces shared by two unit cells:

8 corner x 1/8 atom/corner + 6 faces x 1 atom/face = 4 atoms/unit cell

4 0
3 years ago
In the following reaction 8 grams of ethane are burned and 11 grams of CO2 are collected. What is the percent yield? 2C2H6+7O2=
Alika [10]
47% yield.  
First, let's determine how many moles of ethane was used and how many moles of CO2 produced. Start with the respective atomic weights. 
Atomic weight carbon = 12.0107 
Atomic weight hydrogen = 1.00794 
Atomic weight oxygen = 15.999  
Molar mass C2H6 = 2 * 12.0107 + 6 * 1.00794 = 30.06904 g/mol 
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 g/mol  
Moles C2H6 = 8 g / 30.06904 g/mol = 0.266054387 mol 
Moles CO2 = 11 g / 44.0087 g/mol = 0.249950578 mol  
Looking at the balanced equation, for every 2 moles of C2H6 consumed, 4 moles of CO2 should be produced. So at 100% yield, we should have 0.266054387 / 2 * 4 = 0.532108774 moles of CO2. But we only have 0.249950578 moles, or 0.249950578 / 0.532108774 = 0.46973587 =
46.973587% of what was expected.  
Rounding to 2 significant figures gives 47% yield.
8 0
4 years ago
If your end product is 200.0 g KMnO4 how much KOH did you start with?
aniked [119]

Answer:

m_{KOH}= 142.0gKOH

Explanation:

Hello there!

In this case, according to the following chemical reaction we found on goo gle as it was not given:

2MnO_2+4KOH+O_2\rightarrow 2KMnO4+2KOH+H_2

Whereas we can see a 2:4 mole ratio of potassium permanganate product to potassium hydroxide reactant with molar masses of 158.03 g/mol and 54.11 g/mol respectively. In such a way, by developing the following stoichiometric setup, we obtain the mass of KOH to start with:

m_{KOH}=200.0gKMnO_4*\frac{1molKMnO_4}{158.03gKMnO_4}*\frac{4molKOH}{2molKMnO_4}  *\frac{56.11gKOH}{1molKOH}\\\\m_{KOH}= 142.0gKOH

Best regards!

8 0
3 years ago
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