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Lana71 [14]
3 years ago
5

Using the graph, determine the coordinate of the vertex of the parabola.

Mathematics
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

The coordinates for the vertex are ( -6 , 1 )

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How do you expand polynomials?
d1i1m1o1n [39]

Answer:

Answer is on the pic

Step-by-step explanation:

I hope it's helpful!

8 0
3 years ago
A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they doubled the
mihalych1998 [28]
We can let x be the number of boxes sold for the first week. We can as well express the number of boxes for the second and third week through x using the statements provided.

Since the girl scout sold 5 more boxes on the second week, we have (x + 5) number of boxes sold for the second week. Now, for the third week, since it's double that of the second week, we have 2(x + 5). Thus, we have the following:

first week: x
second week: x + 5
third week: 2(x + 5)

Given that the total number of boxes sold for the three weeks is 431. We have

x + (x + 5) + 2(x + 5) = 431
x + x + 5 + 2x + 10 = 431
4x + 15 = 431
4x = 431 - 15
4x = 416
x = 104

We have now the value of x. Using this, we can find the values for the second and third week.
x + 5 = `104 + 5 = 109
2(x + 5) = 2(109) = 218

Answer: 
first week: 104
second week: 109
third week: 218



5 0
3 years ago
What is the answer to twenty one tenths subtracting nine fifths
Sauron [17]
2 2/5 idk how you do it in your school but that js how i do it
7 0
3 years ago
Write an equation in slope-intercept form for the line with y-intercept −5 and slope −2/5
riadik2000 [5.3K]

Answer:

\large\boxed{y=-\dfrac{2}{5}x-5}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have

m=-\dfrac{2}{5},\ b=-5

Substitute:

y=-\dfrac{2}{5}x+(-5)}=-\dfrac{2}{5}x-5

8 0
3 years ago
[Geometry Basics] I'm just checking if this is correct:
Leno4ka [110]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ x &,& y~) &#10;%  (c,d)&#10;&&(~ -9 &,& -1~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-9+x}{2}~~,~~\cfrac{-1+y}{2} \right)=\stackrel{midpoint}{(8,14)}\implies &#10;\begin{cases}&#10;\cfrac{-9+x}{2}=8\\\\&#10;-9+x=16\\&#10;\boxed{x=25}\\&#10;-------\\&#10;\cfrac{-1+y}{2} =14\\\\&#10;-1+y=28\\&#10;\boxed{y=29}&#10;\end{cases}

\bf -------------------------------\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ x &,& y~) &#10;%  (c,d)&#10;&&(~10 &,& 12~)&#10;\end{array}\qquad&#10;\\\\\\&#10;\left( \cfrac{10+x}{2}~~,~~\cfrac{12+y}{2} \right)=\stackrel{midpoint}{(6,9)}\implies &#10;\begin{cases}&#10;\cfrac{10+x}{2}=6\\\\&#10;10+x=12\\&#10;\boxed{x=2}\\&#10;-------\\&#10;\cfrac{12+y}{2} =9\\\\&#10;12+y=18\\&#10;\boxed{y=6}&#10;\end{cases}
3 0
3 years ago
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