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3 years ago

Plz help! Will mark brainliest! Please subtract and simplify

Mathematics

2 answers:

FinnZ [79.3K]3 years ago

6 0

a2−2a−3a divided by 2−9a+18−(a2−5a−6a2+9a+8)=21a3−70a2−7a+84 divide by a4−55a2+90a+144=7(a+1)(a−3)(3a−4) divide by (a+1)(a−3)(a−6)(a+8)answer =21a−28 divided by a2+2a−48

Sloan [31]3 years ago

4 0

I think it's -11a + 17

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A horses body temperature T, is considered to be normal if it is within at least 0.9 degrees Fahrenheit of 99.9 degrees Fahrenhe

geniusboy [140]

99.9+0.9=100.8 degrees fahrenheit
99.9-0.9+99 degrees fahrenheit

The temperature can be between 99 and 100.8 degrees Fahrenheit.
100.8-99=1.8degrees (range)

99≤T≥100.8

4 0

3 years ago

The area of a rectangle is 1,357 square feet. The length is 59 feet. What is the width?

dangina [55]

Answer:

w = 23

Step-by-step explanation:

a = l × w

The area and length are given, so you can substitute them in.

1357 = 59 × w

Solve for w:

w = $\frac{1357}{59}$

w = 23

3 0

3 years ago

Read 2 more answers

You have a bag which contains 15 slips of paper that are num- bered 1 through 15. You pull a piece of paper from the bag, do not

BARSIC [14]

Answer:

The correct answer is 1/35 (fully simplified fraction)

Step-by-step explanation:

Number of slips of paper in the bag = 15

Number of slips of paper in the bag that are a multiple of 4 = 3 (those numbered 4, 8 and 12)

Using Laplace Rule, that states that the probability of an event X is obtained by dividing the number of results that form event X by the number of possible outcomes, provided that the elementary events are equiprobable, that is, that all possible outcomes have the same probability.

Probability of pulling a 1st piece of paper multiple of 4 = 3/15 = 1/5

Now we have a second event Y that is not independent from the first event X, because now the number of slips is 14 and not 15, you're not returning the first slip of paper.

Probability of pulling a 2nd piece of paper multiple of 4 = Probability of the 1st event * probability of the 2nd event after it happened the 1st one

Probability of pulling a 2nd piece of paper multiple of 4 = 1/5 * 2/14

Probability of pulling a 2nd piece of paper multiple of 4 = 2/70 = 1/35

The probability of pulling two slips of paper both numbered with a multiple of 4 is 1/35.

3 0

3 years ago

Suppose we want to choose 4 colors, without replacement, from 18 distinct colors.

amm1812

Answers:

(a) 73440
(b) 3060

=====================================================

Explanation for part (a)

Consider four slots labeled A,B,C,D.

We have

18 choices for slot A
17 choices for slot B
16 choices for slot C
15 choices for slot D

We started at 18 and counted down until we filled the four slots. The countdown is because we cannot repeat a color. Multiply out those values to get the answer: 18*17*16*15 = 73440

You can use the nPr permutation formula as an alternative method

$_nP_r = \frac{n!}{(n-r)!}$

in this case n = 18 and r = 4. The exclamation marks indicate factorial.

-----------------------------------

Explanation for part (b)

Let's say we had color labels A,B,C,... all the way up to R which is the 18th letter in the English alphabet. From those 18 letters, we can only pick four. Let's say we pick D,E,F,G.

Focusing solely on the set {D,E,F,G}, we only have one set and the order doesn't matter. So {D,E,F,G} is the same as {D,E,G,F}.

There are 4*3*2*1 = 24 ways to arrange those four items meaning that we'll need to divide the result of part (a) by 24 to get the result of part (b)

73440/24 = 3060

You could use the nCr combination formula to get the same result

$_nC_r = \frac{n!}{r!(n-r)!}$