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evablogger [386]
3 years ago
7

What are the coordinates of point B on AC such that the ratio of AB to BC is 2:3

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

B(4, - 3 )

Step-by-step explanation:

We have A(2, - 7) and C(7, 3 )

Using the section formula to calculate the coordinates of B

=  =  =  = 4

=  =  =  = - 3

Hence B(4, - 3 )

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Need Help please answer
djverab [1.8K]
For the 2nd part of 2. just plug in what you have for G in your previous graph into the equation. This will give you H for all 5 columns . Like 3×8(-1+5)= h = 3× 32= 96 so H should equal 96 and so on as far as this function.

For number 3. The equation is given so just plug in your T for time which is 3 seconds, so...-16(3)^2+90(3) = H the height at 3 seconds. I'm doing it in my head but should be the height is 414. You should also say whether it's ft or inches etc because the teacher or yourself left that out of the equation which is also vital lol.
6 0
3 years ago
How do I factor x^4-5x^2+6?
Vilka [71]

Answer:

=(x^2-3)(x^2-2)

Step-by-step explanation:

So we have the expression:

x^4-5x^2+6

And we wish to factor it.

First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

=u^2-5u+6

This is a technique called quadratic u-substitution. Now, we can factor in this form.

We can use the numbers -3 and -2. So:

=u^2-2u-3u+6

For the first two terms, factor out a u.

For the last two terms, factor out a -3. So:

=u(u-2)-3(u-2)

Grouping:

=(u-3)(u-2)

Now, substitute back the x² for u:

=(x^2-3)(x^2-2)

And this is the simplest form.

And we're done!

3 0
3 years ago
Evaluate k = 13 helllp noww
OverLord2011 [107]

Answer:

-13

Step-by-step explanation:

4 0
3 years ago
if in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99%
Dahasolnce [82]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.

If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?

Given Information:

standard deviation = σ = 30 hours

confidence level = 99%

Margin of error = 6 hours

Required Information:

sample size = n = ?

Answer:

sample size = n ≈ 165

Step-by-step explanation:

We know that margin of error is given by

Margin of error = z*(σ/√n)

Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size

√n = z*σ/Margin of error

squaring both sides

n = (z*σ/Margin of error)²

For 99% confidence level the z-score is 2.576

n = (2.576*30/6)²

n = 164.73

since number of bulbs cannot be in fraction so rounding off yields

n ≈ 165

Therefore, a sample size of 165 bulbs is needed to ensure a margin of error not greater than 6 hours.

3 0
3 years ago
(3ab+2c)^3 what is the answer
svet-max [94.6K]

Answer:

=27a^3b^3+54a^2b^2c+36abc^2+8c^3

Step-by-step explanation:

(3ab+2c)^3

=(3ab+2c) × (3ab+2c) ×

=(3ab+2c)(9a^2b^2+12abc+4c^2)

=(3ab)(9a^2b^2)+(3ab)(12abc)+(3ab)(4c^2)+(2c)(9a^2b^2)+(2c)(12abc)+(2c)(4c^2)

=27a^3b^3+36a^2b^2c+12abc^2+18a^2b^2c+24abc^2+8c^3

=27a^3b^3+54a^2b^2c+36abc^2+8c^3

<em>hope this helps....</em>

5 0
3 years ago
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