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iren2701 [21]
3 years ago
12

Find the gradients of lines A and B.

Mathematics
1 answer:
kherson [118]3 years ago
5 0
Hey, you didn’t provide any picture or further context.

To solve for gradient, do (y2-y1)/(x2-x1)
So what do you think?
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What is the next term of the geometric sequence? 40/27, 20/9, 10/3, ??
kodGreya [7K]

Answer:

3/1

Step-by-step explanation:

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Pachacha [2.7K]

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Step-by-step explanation:

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3 years ago
What is 4/5 x 1 1/6=
andrew11 [14]
4/5 x 1 1/6 
<span>= 4/5 x (6 x 1 + 1)/6 </span>
<span>= 4/5 x 7/6 </span>
<span>= (4 x 7)/(5 x 6) </span>
<span>= 28/30 </span>
<span>= (28 ÷ 2)/(30 ÷ 2) </span>
<span>= 14/15</span>
6 0
3 years ago
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Simplify the following expression 7a + 5b - 2a + b
Papessa [141]
5a+6b would be the simplified answer
7 0
1 year ago
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For what value of x will the function f(x) = -3(x - 10)(x - 4) have a maximum value? Find the maximum value.
gayaneshka [121]

Hello!

To find the maximum value of the function f(x) = -3(x - 10)(x - 4), the easiest way is to find the vertex using the formula: x = -b/2a.

Firstly, we need to simplify f(x).

f(x) = -3(x - 10)(x - 4)

f(x) = -3(x² - 14x + 40)

f(x) = -3x² + 42x + -120

Since the equation f(x) is now simplified to standard form, we can find the vertex.

a = -3, b = 42, and c = -120

x = -(42)/2(-3) = -42/-6 = 7

Then, we substitute 7 into the the function f(x) = -3(x - 10)(x - 4), or

f(x) = -3x² + 42x + -120, to find the y-value of the vertex.

f(x) = -3(7 - 10)(7 - 4)

f(x) = -3(-3)(4)

f(x) = 27

The vertex of f(x) is (7, 27).

Therefore, the maximum x-value for the function f(x) is 7.

4 0
3 years ago
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