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3 years ago

Wats is the answer to this question

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

3 0

Simplify the radical by breaking the radicand up into a product of known factors in other words take the cube root of 27 then for the exponent 9 you divide by 3 get

3x^3

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Factor 64 - P.<br> (8 - x(8 - x)<br> (8 + x (8 - x)<br> (X + 8)(x-8)

muminat

Question:

Factor $64-x^2$

(8 - x)(8 - x)

(8 + x) (8 - x)

(X + 8)(x-8)

Answer:

Option B: $(8+x)(8-x)$ is the factor

Explanation:

Given that the expression is $64-x^2$

We need to find the factor of the given expression.

Let us rewrite the expression as $8^2-x^{2}$

Since the expression is of the form $a^2-b^2$ , let us use the identity $a^2-b^2=(a+b)(a-b)$

where a = 8 and b = x

Substituting the values in the identity, then the expression can be written as

$8^2-x^{2}=(8+x)(8-x)$

Thus, the factor of the expression is $(8+x)(8-x)$

Hence, Option B is the correct answer.

4 0

3 years ago

Pls help me with this question ASAP!!!

MA_775_DIABLO [31]

Answer:

up the price will go up making the x value go up

5 0

3 years ago

Jenny uses 7/9 gallon of water to water roses

jeka94

8 0

3 years ago

Pls help! need answer ASAP!!

yuradex [85]

Answer:

c because if you subtract

7 0

3 years ago

Which is equivalent to √3/√8 when denominator is "rationalized"?

TEA [102]

Step-by-step explanation:

$\dfrac{\sqrt3}{\sqrt8}=\dfrac{\sqrt3\cdot\sqrt2}{\sqrt8\cdot\sqrt2}=\dfrac{\sqrt{3\cdot2}}{\sqrt{8\cdot2}}=\dfrac{\sqrt6}{\sqrt{16}}=\dfrac{\sqrt6}{4}$

$\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\ \text{for}\ a\geq0\ \wedge\ b\geq0\\\\\sqrt{a}=b\iff b^2=a\ \text{for}\ a\geq0\ \wedge\ b\geq0\\\\\sqrt{16}=4\ \text{because}\ 4^2=16$

4 0

3 years ago