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The question is incomplete. Here is the complete question.
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.
a) Determine the arc length to the nearest tenth of an inch.
b) Explain why the following proportion would solve for the length of AC below:
c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.
Note: The image in the attachment shows the arc to solve this question.
Answer: a) 9.4 in
c) x = 13.6 in
Step-by-step explanation:
a) , where:
r is the radius of the circumference
mAB is the angle of the arc
arc length =
arc length =
arc length = 9.4
The arc lenght for the image is 9.4 inches.
b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):
c) Resolving (b):
x =
x = 13.6
The arc length for the image is 13.6 inches.
Answer:
A = 108 units²
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A = h (b₁ + b₂ )
where h is the height between the 2 bases and b₁, b₂ are the parallel bases
Here h = 24 , b₁ = 8 , b₂ = 1 , then
A = × 24 × (8 + 1) = 12 × 9 = 108 units²