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kondaur [170]
3 years ago
13

State a value that would make the following inequality true:

Mathematics
1 answer:
kvv77 [185]3 years ago
4 0
It can be any large number. Such as 1000 because 1000 - 93 = 907 therefore 907 is greater than 175

Work:
1000-93=907
907>175

Hope this helps!!! :)
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A pound of weed and feed covers 200 square feet how many pounds are needed to fertilize a lawn measuring 70 feet by 50 feet
nika2105 [10]
You would have to find out how many square feet the lawn is first:
70 x 50 = 3500 square feet
You are told that one pound = 200 square feet so use this to calculate how many pound you’ll need for 3500 square feet.
3500 square feet divided by 200 square feet = 17.5 pounds
Answer: 17.5 pounds
5 0
3 years ago
Find the perimeter of the rectangle
Oksanka [162]
11+11+4+4=30 so the answer is thirty 
8 0
3 years ago
Read 2 more answers
If the measure of angle 1 is 110 degrees and the measure of angle 3 is (2 x + 10) degrees, what is the value of x?
user100 [1]

Answer:

Correct option is

B

90

∘

,90

∘

,90

∘

Let AB and CD be two lines Intersecting at O, such that, ∠AOD=90

∘

Now, ∠AOD=∠COB=90

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(Vertically opposite angles)

⟹∠AOD+∠DOB=180

o

(Angles on a straight line)

⟹90+∠DOB=180

o

∠DOB=90

∘

∠DOB=∠AOC=90

∘

(Vertically opposite angles)

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.

7 0
2 years ago
The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
According to the National Retail Federation, the average shopper will spend $1,007.24 during the holiday shopping season. What i
Mazyrski [523]

Based on the amount predicted to be spent, the hypotheses will be:

  • Null Hypothesis = $1,007.24
  • Alternate Hypothesis ≠ $1,007.24

The Null Hypothesis is the one that confirms the prediction so in this case it will be that the average shopper will indeed spend $1,007.24.

The Alternate Hypothesis theorizes that the event being predicted will not happen so in this case that would mean that the shopper would not spend $1,007.24.

In conclusion, the null hypothesis confirms and the alternate denies.

<em>Find out more on the null hypothesis at brainly.com/question/15980493.</em>

7 0
3 years ago
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