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eduard
3 years ago
10

point p is located at (x, y). The point is reflected in the y-axis. Point P’s image is located at (__?__)

Mathematics
2 answers:
lesya [120]3 years ago
3 0

Answer:

-x,y?

Step-by-step explanation:

if it's being reflected across the y-axis then that should go in to the negative side of the graph and the same if its being reflected across the x-axis, in which case it would be x,-y

deff fn [24]3 years ago
3 0

Answer:

P'(-x,y)

Step-by-step explanation:

The question is asking you to reflect over the y-axis. You pick a random point in the first quadrant and reflect that point over the y-axis. The point will land in the second quadrant and the x-value will have been negated (changed sign).

Ex.

(5,4) would become (-5,4)

P(x,y) reflected over the y-axis P'(-x,y)

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In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

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We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

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a=\frac{2S -2v_ot-2s_o}{t^2}

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