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3 years ago

What is true if a liquid and gas are in equilibrium

Chemistry

2 answers:

Olin [163]3 years ago

8 0

Liquid molecules forming a gas and gas molecule forming a liquid are equal in number.

RUDIKE [14]3 years ago

5 0

Forming in liquid are equal in numbef

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Calculate the pH of substance one if it has an [OH-] that is equal to 3.2* 10^-8

damaskus [11]

Answer:

pH = 6.5

Explanation:

Given data:

pH of substance = ?

[OH⁻] concentration = 3.2×10⁻⁸

Solution:

pOH = -log[OH⁻]

pOH = -log[3.2×10⁻⁸]

pOH = 7.5

we know that,

pH + pOH = 14

pH = 14- pOH

pH = 14 - 7.5

pH = 6.5

7 0

3 years ago

4. Since water possess a partially positive and a negative end, we refer to it as?

Elanso [62]

Answer:

A polar molecule

Explanation:

8 0

2 years ago

Chlorine, which has an atomic mass of 35.453 amu, has two naturally occurring isotopes, Cl-35 and Cl-37. Which isotope occurs in

Pachacha [2.7K]

Cl-35 occurs in greater abundance.

The weighted atomic mass lies closer to 35 u than to 37 u, so the Cl-35 isotope must be more abundant.

8 0

3 years ago

Why carbon dioxide can be tested with the help of moist blue litmus paper ?

Evgesh-ka [11]

Answer:

carbon dioxide is acidic and when it comes in contact with blue litmus paper it turns red

Explanation:

4 0

4 years ago

two perfumes A and B were released at the same time and you are standing 7.5metres away from both of them.molarmass of perfume A

kifflom [539]

17.40 sec is the time will take to smell second perfume after diffusion takes place

Acc. to Graham's law of Diffusion

Diffusion of Gas inversely proportional to square root of its Molecular mass.

rb (Perfume B)

ra(perfume A)

= $\sqrt{\frac{Ma}{Mb} }$ its equation (1)

Give molar mass of Perfume A = 275 g/mol

molar mass of Perfume B= 205g/mol putting value in (1)

» $\frac{rb}{ra}=\sqrt{\frac{275}{205} }$

$\frac{rb}{ra} =1.16$ its eq (2)

» Perfume B will defuse 1:16 times faster than perfume A.

Hence, perfume B will be first smelled by Person.

Sf Equal volume V of two goes diffuse in t1 and t2 sec. respectively ton

$\frac{ra}{rb}=\frac{tb}{ta}$

Now,, from eq(2) toto

1/1:15 = $\frac{tb}{ta}$

Given tb =the smell of Perfume B as it diffuse faster

ta= 1.15 x 15 see

=ta2=17.40 sec

Learn more about diffuse here

brainly.com/question/3266850

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4 0

1 year ago