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3 years ago

Convert fraction with numerator 7 and denominator 8 to a decimal.

Mathematics

1 answer:

castortr0y [4]3 years ago

6 0

All you have to do is divide 7 by 8 (so 7/8) and you get the answer: 0.875! hope that helps! :)

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I need help with 3x-2y=24

nasty-shy [4]

Answer:

y= 3/2x -12

Step-by-step explanation:

subract x then u got -2y=-3x+24

divide everythang by -2

then u got y=3/2x -12

5 0

2 years ago

HELPP PLSSMFCODSM MATH TEST !

tresset_1 [31]

Answer:

17= addition

18 = 27

Let's solve your equation step-by-step.

43x−4=5−x

Step 1: Simplify both sides of the equation.

43x−4=5−x

43x+−4=5+−x

43x−4=−x+5

Step 2: Add x to both sides.

43x−4+x=−x+5+x

73x−4=5

Step 3: Add 4 to both sides.

73x−4+4=5+4

73x=9

Step 4: Multiply both sides by 3/7.

(37)*(73x)=(37)*(9)

x=277

Answer:

x=277

6 0

2 years ago

Sarah and amanda each have 2 bags with 4 marbles in each .how many marbles do they have altogether?

OLEGan [10]

16 marbles...................

7 0

3 years ago

One of Julian's friends also has a rectangular aquarium. The dimensions of his friend's tank are each exactly 1 1/4 times the di

daser333 [38]

Answer:

468.75 square inches

Step-by-step explanation:

Let the length of Julian's tank be x

Let the width of Julian's tank be y

So, Area of Julian's tank= $Length \times Width =xy$

Since we are given that Julian's tank is approximately 300 square inches

So, $xy=300$ --1

Now we are given that The dimensions of his friend's tank are each exactly $1\frac{1}{4} =\frac{5}{4}$ times the dimensions of Julian's tank.

So,length of his friend's tank = $\frac{5}{4}x$

So,width of his friend's tank = $\frac{5}{4}y$

So, Area of his friend's tank= $\frac{5}{4}x \times \frac{5}{4}y$

= $\frac{25}{16}xy$

= $\frac{25}{16}(300)$ (Using 1)

= $468.75$

Hence the approximate area of the rectangular base of his friend's tank is 468.75 square inches.

So, Option D is correct.

8 0

3 years ago

Angle CED is a right angle, AB congruent to CD, DB bisects AC at E Prove: Quadrilateral ABCD is a Rhombus

Anika [276]

Properties of Rhombus:
1) A flat shape with 4 equal straight sides. It looks like a kite or a diamond.
2) all sides have equal length
3) opposite sides are parallel and opposite angles are equal
4) the diagonals bisect each other at a right angle.
5) the altitude is the distance at right angles to two sides

∠CED is a right angle : GIVEN
AB congruent to CD : all sides have equal length
DB bisects AC at E : diagonals bisect each other at a right angle.

4 0

2 years ago