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sattari [20]
3 years ago
13

The difference of two positive numbers is 7 and the sum of their squares is 109. Find the numbers.

Mathematics
1 answer:
Ray Of Light [21]3 years ago
7 0

Answer:

Numbers\ are\ 58\ and\ 51.

Step-by-step explanation:

The the numbers are x\ and\ y.

<em>Difference:</em>

<em></em>Difference\ of\ numbers=7\\\\x-y=7....................eq(1)<em></em>

<em>Sum:</em>

<em></em>Sum\ of\ numbers=109\\\\x+y=109...........................eq(2)<em></em>

<em></em>

Solve eq(1) and eq(2).

eq(1)+eq(2)\\\\x-y+x+y=7+109\\\\2x=116\\\\x=58\\\\Now\ from\ equation\ 1\\\\x-y=7\\\\y=x-7\\\\y=58-7\\\\y=51

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X = 10<br><br> x = 2<br><br> x = two divided by five.<br><br> x = 11
KengaRu [80]

Answer:

x = 10

Step-by-step explanation:

You can try the answers to see which works. (The first one does.)

Or, you can solve for the variable:

Divide by 75

... (1/5)^(x/5) = 3/75 = 1/25

Recognize that 25 = 5^2, so ...

... (1/5)^(x/5) = (1/5)^2

Equating exponents, you have

... x/5 = 2

... x = 10 . . . . . multiply by 5

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You can also start by taking logarithms:

... log(75) +(x/5)log(1/5) = log(3)

... (x/5)log(1/5) = log(3) -log(75) = log(3/75) = log(1/25) . . . . simplify the log

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"Equating exponents" is essentially the same as taking logarithms.

5 0
3 years ago
What is the solution to 6x − 8 &gt; 4x + 26
S_A_V [24]

Answer:

x > 17

Step-by-step explanation:

Combine like terms,  We get:

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8 0
3 years ago
Ethan is 40 years old. His son is 12 years old. How many years ago was Ethan 5 times older than his son?
ella [17]
X=number of years that Ethas was 5 times older than his son.
we suggest this equation:

40-x=5(12-x)
40-x=60-5x
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answer. 5 years. 

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Answer:

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Step-by-step explanation:

5 0
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