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kolbaska11 [484]
3 years ago
15

4^2[1/3+4(36÷6)] Show work please.

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

1168/3 or 389 1/3 as a mixed fraction

Step-by-step explanation:

Simplify the following:

4^2 (4×36/6 + 1/3)

4×36/6 = (4×36)/6:

4^2 ((4×36)/6 + 1/3)

4^2 = 16:

16 ((4×36)/6 + 1/3)

36/6 = (6×6)/6 = 6:

16 (4×6 + 1/3)

4×6 = 24:

16 (24 + 1/3)

Put 1/3 + 24 over the common denominator 3. 1/3 + 24 = 1/3 + (3×24)/3:

16 1/3 + (3×24)/3

3×24 = 72:

16 (1/3 + 72/3)

1/3 + 72/3 = (1 + 72)/3:

16 (1 + 72)/3

1 + 72 = 73:

16×73/3

16×73/3 = (16×73)/3:

(16×73)/3

| | 7 | 3

× | | 1 | 6

| 4 | 3 | 8

| 7 | 3 | 0

1 | 1 | 6 | 8:

Answer:  1168/3

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2 years ago
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B

Step-by-step explanation:

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1 year ago
A scientist has a sample of bacteria that initially contains 10 million microbes. They observe the sample and finds that the num
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Answer:

M(t) = 6.7 * 10⁷ (67 million)

Minutes (t) =55

Step-by-step explanation:

1. Write an exponential equation that represents M, the total number of bacterial microbes in millions, as a function of t, the number of minutes the sample has been observed.

For answering this question, we will use the following formula:

M(t) = B₀ * g ^(t/m), where:

•M(t) represents the total number of bacterial microbes in millions.

• B₀ represents the initial population of bacteria in millions.

• g represents the growth factor.

• t represents the total number of minutes we will observe the bacteria growing.

• m represents the time in minutes it takes to the growth factor g to occur.

2. Then, determine how much time, to the nearest minute, will pass until there are 67 million bacterial microbes.

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Replacing with the values we know:

6.7 * 10⁷ = 10⁷ * 2 ^(t/20)

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ln 6.7 = ln 2 ^(t/20)

ln 6.7 = t/20 ln 2

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3 0
3 years ago
If f(x) = 2x and g(x) = 5x + 2, what is (f + g)(x) when x = 3?
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How long is the segment from(-5,2)to(-5,-8)
dusya [7]

Answer:

10

Step-by-step explanation:

To calculate the distance d use the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 5, 2) and (x₂, y₂ ) = (- 5, - 8)

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