Find the area of a triangle with the vertices a(0,2), b(8,2), and C(4-3)

2 answers:

4 0

Height of the triangle with AB as base = 2 – (–3) => 5

<span>Area = (1/2) * base * height => (1/2) * 8 * 5 ==> 20 sq. units. </span>

Dimas [21]3 years ago

3 0

First, consider (0,2) and (8,2). The y-value is the same for both points. x ranges from 0 to 8, so the length of this horizontal side of the triangle is (8-0), or 8.

Again, this horiz. side has a y-value of 2.
The third point is (4,-3). Therefore the vertical distance from the horizontal line to the third point is 2 - (-3), or 5.

Thus, the "base" of the triangle is 8 and the "height" is 5.

The area is A = (bh)/2. Substitute the values 8 and 5. Simplify your result. Answer: 20 square units.

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As per given,

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