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Nata [24]
3 years ago
13

A 16 in by 20 in photo is reduced so that the length( the longer dimension) is 12 in.

Mathematics
1 answer:
sdas [7]3 years ago
7 0
B 9.2 in will be your answer for the test
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What is the answer of this equation
SSSSS [86.1K]
Put it in an improper fraction by multiply the coefficient with the denominator and add the numerator.
5/2 , 14/3
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15/6 + 28/6 = 43/6
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Find the greatest common factor of <br><br> 2x^2-8x
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Answer:

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A store that buys and sells used video games buys a game at a cost of ​$19 and sells it at a selling price of ​$23. Find the mar
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3 years ago
Read 2 more answers
Solve 0=4x^2+12x+9 using the quadratic formula.
MAXImum [283]
The quadratic formula is x =  \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}.  With the values from this equation plugged in, it looks like this:

x = \frac{-12 \pm \sqrt{12^2 - 4(4)(9)} }{2(4)} \\  \\ x = \frac{-12 \pm \sqrt{144 - 144} }{8}  \\  \\ x =  \frac{-12}{8}  \\  \\ x = - \frac{3}{2}

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7 0
3 years ago
Ac method for x^2+20x-8=0
yanalaym [24]
<h2>Explanation:</h2><h2></h2>

By using quadratic formula:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\quad a=1,\:b=20,\:c=-8

x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}

x=\frac{-20+\sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}:\quad 2\left(3\sqrt{3}-5\right)

x=\frac{-20-\sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}:\quad -2\left(5+3\sqrt{3}\right)

So the solutions are:

\boxed{x=2\left(3\sqrt{3}-5\right),\:x=-2\left(5+3\sqrt{3}\right)}

5 0
3 years ago
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