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Eva8 [605]
3 years ago
12

8^2 x (2+6) / 4solve

Mathematics
1 answer:
Softa [21]3 years ago
3 0

Answer:

8^2\times \frac{\left(2+6\right)}{4}

\frac{\left(2+6\right)}{4} = 8/4 = 2

8^2 \times 2 =

64 x 2 =

128.

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Irina18 [472]
1/3 is the rate of change. the rate of change is the slope of an equation
4 0
3 years ago
The coordinates of G are
Lorico [155]

The coordinates of vertex G are (2,0). I did this.

3 0
3 years ago
Best explained and correct answer gets brainliest!!!Which choice is the equation of a line that passes through the point (5, -1)
Softa [21]

y = -x + 5

Slope of this line = - 1.

Slope of the line that is perpendicular is negative reciprocal.

For example if slope= a/b, then slope of the perpendicular line = -b/a.


For our line, the slope is going to be -(-1)=1.


y=mx +b

m=1

y=x+b


We need to find b. We are going to use point (5, -1).

y = x +b

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So,

y= x - 6


Answer is A.



5 0
3 years ago
Find the area of the following regions, expressing your results in terms of the positive integer n ≥ 2. The region bounded by
cluponka [151]

Answer:

The area of the searched region is A= a+b+ \frac{2n}{n+1}- \frac{n(a^{\frac{n+1}{n} }+b^{\frac{n+1}{n} }) }{n+1}-2

Step-by-step explanation:

If you want to find the area of a region bounded by functions f(x) and G(x) between two limits (a,b), you have to do a double integral. you must first know which of the functions is greater than the other for the entire domain.

In this case, for 0<x<1, f(x)<g(x)

while for 1<x, g(x)<f(x).

Therefore if our domain is all real numbers superior to 0 (where the limit 0<a<1 and 1<b), we have to do 2 integrals:

A=A(a<x<1)+A(1<x<b)

A(a

A(1

A=a-1 +\frac{n}{n+1} - \frac{na^{\frac{n+1}{n} } }{n+1} +  b-1 + \frac{n}{n+1} - \frac{nb^{\frac{n+1}{n} } }{n+1} = a+b+ \frac{2n}{n+1}  - \frac{n(a^{\frac{n+1}{n} }+b^{\frac{n+1}{n} }) }{n+1}   -2

3 0
3 years ago
What is the greatest possible integer value of x for which square root of √x-5 is an imaginary number
umka21 [38]
The correct answer for this question is 4.

We have to bear in mind that any number  should be less than 5 to make the square root be an imaginary number.
Starting with 4
= square root (4 - 5)
= square root (-1)
= imaginary 

4 0
3 years ago
Read 2 more answers
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