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bagirrra123 [75]
3 years ago
15

How do you work these types of problems out?

Mathematics
1 answer:
vitfil [10]3 years ago
5 0

Answer:

3,000 kg (3.14)+1.5m^3  and that is math!

Step-by-step explanation:

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Is there a way to find all the factor pairs for a big number like 805 quickly
Mars2501 [29]

Answer:

The complete list of factors for 805 are 1, 5, 7, 23, 35, 115, 161, and 805.

Step-by-step explanation:

A factor pair is a combination of two factors which can be multiplied together to equal 805. In proper math terms, the number 805 is called the product and the two numbers that can be multiplied together to equal it are called the factors.

In order to work out the factor pairs of 805 we need to first get all of the factors of 805. Once you have the list of all those factors we can pair them together to list out all of the factor pairs.

The complete list of factors for 805 are 1, 5, 7, 23, 35, 115, 161, and 805.

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2 years ago
Solve the formula for the red variable (a). *<br> 23. P= a + b + c<br> Your answer
Len [333]

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33

Step-by-step explanation:

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3 years ago
HELP ASAPPPP PLEASE
Lerok [7]

Answer:

I don't know but i think the answer is:

3/8 and 1/2

Step-by-step explanation:

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3 years ago
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3 years ago
Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC
e-lub [12.9K]

Answer:

DC=\frac{8}{3}\ units

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

BM^2=AB^2-AM^2

we have

AB=5\ units\\AM=x\ units

substitute

BM^2=5^2-x^2

BM^2=25-x^2 -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

BM^2=BC^2-MC^2

we have

BC=7\ units\\MC=AC-AM=(9-x)\ units

substitute

BM^2=7^2-(9-x)^2

BM^2=49-(81-18x+x^2)  

BM^2=49-81+18x-x^2

BM^2=-x^2+18x-32 ----> equation B

equate equation A and equation B

-x^2+18x-32=25-x^2

solve for x

18x=25+32\\18x=57\\\\x=\frac{57}{18}

Simplify

x=\frac{19}{6}

<em>Find the length of DC</em>

DC=AC-2x

substitute the given values

DC=9-2(\frac{19}{6})

DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units

8 0
3 years ago
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