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Sever21 [200]
4 years ago
15

Can someone help me please

Mathematics
1 answer:
Schach [20]4 years ago
7 0

Answer:

Step-by-step explanation:

The system of equations is expressed as

y=-2x+7 - - - - - - - - 1

y=5x-7 - - - - - - - - -2

We would equate equation 1 and equation 2. It becomes

- 2x + 7 = 5x - 7

We would add 2x to the left hand side and the right hand side of the equation. Also add 7 to the left hand side and the right hand side of the equation. It becomes

- 2x + 2x + 7 + 7 = 5x + 2x - 7 + 7

14 = 7x

Dividing the left hand side and the right hand side of the equation by 7, it becomes

7x/7 = 14/2

x = 2

y= -2 × 2 + 7

y = - 4 + 7

y = 3

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Write the equation of a line with a slope of 3 that passes through (-3,2).
ratelena [41]

Answer:

y = 3x + 11

Step-by-step explanation:

Substitute the information into the point-slope form equation.

Point-slope form: y - y₁ = m(x - x₁)

y - 2 = 3(x - (-3))

y - 2 = 3(x + 3)

y - 2 = 3x + 9

y = 3x + 11

6 0
3 years ago
How many full 5/8 ft pieces of wood can you cut from a board that is 458 feet long?
tankabanditka [31]

Answer:

732 pieces

Step-by-step explanation:

458/5/8

= 458* 8/5= 732 pieces

if my answer helps please mark as brainliest

8 0
3 years ago
Read 2 more answers
Help please really needed
Y_Kistochka [10]

Answer:

the answer is C hope this helps

5 0
3 years ago
Unfortunately, arsenic occurs naturally in some ground water†. A mean arsenic level of µ = 8.0 parts per billion (ppb) is consid
professor190 [17]

Answer:

Check the explanation below.

Step-by-step explanation:

Hello!

The study variable is:

X: Arsenic level of well water (ppb)

If the mean concentration of arsenic is 8 ppb then the water is considered safe to use for agricultural use.

In texas a sample of 36 tests for arsenic was taken to see if the average level of arsenic of the water well is less than 8 ppb, symbolically μ < 8

The hypothesis is:

a)

H₀: μ ≥ 8

H₁: μ < 8

Level of significance is α: 0.05

b)

To study the population mean the variable needs to have at least a normal distribution. If the information of the sample was available we could make a normality test to check if it's distribution is normal or not. Since the Students t cannot be used unless the variable has a normal distribution, we cannot choose this statistic to make the hypothesis test, the same happens with the standard normal, if the condition of a variable with normal distribution is not met, the statistic cannot be used.

The most recommendable is to apply the Central Limit Theorem, this theorem states:

Be a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

X[bar]≈N(μ; σ²/n)

Then you can use the standard normal approximation:

Z=  X[bar] - μ ≈N(0;1)

σ/√n

The critical region for this test is one-tailed (left tail)

Z_{\alpha } = Z_{0.05}= -1.645

If Z_{H_0} \leq -1.645\\, you reject the null hypothesis.

If Z_{H_0} > -1.645, you do not reject the null hypothesis.

c)

The statistic is:

Z= \frac{7.3-8}{\frac{2.4}{\sqrt{36} } }

Z= -1.75

The p-value is one-tailed with the same direction of the test, you calculate it as:

P(Z < -1.75)= 0.04006

To decide using the p-value you have to compare it against the significance level.

If it is greater than the level of significance, then you don't reject the null hypothesis.

If it is equal or less than the level of significance, then you reject the null hypothesis.

d) The calculated p-value (0.04006) is less than α (0.05), the decision is to reject the null hypothesis.

e) At a level of 5%, the decision is to reject the null hypothesis. This means that there is significant evidence to think that the average level of arsenic in the well water is less than 8 ppb.

I hope it helps!

4 0
3 years ago
Beginning inventory10 units @ $10 per unit First purchase35 units @ $11 per unit First sale20 units Second purchase40 units @ $1
il63 [147K]

Answer:

option C

Step-by-step explanation:

given,

Beginning inventory             10 units @ $10 per unit

First purchase                        35 units @ $11 per unit

Second purchase                  40 units @ $12 per unit

Third purchase                       15 units @ $13 per unit

first sale = 20 units

second sale = 35 units

now,

unit left after first sale = 35 - 20 = 15 units @ $11 per unit

unit left after second sale = 40 - 35 = 5 @ $12 per unit

third purchase =  15 units @ $13 per unit

inventory  = 10 units @ $10 per unit + 15 units @ $11 per unit + 5 @ $12 per unit + 15 units @ $13 per unit

                = 100 + 165 + 60 + 195

                = $ 520

hence, the correct answer is option C

8 0
3 years ago
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