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4 years ago

Can any one help me on these two PleaseI

Mathematics

2 answers:

Inessa05 [86]4 years ago

8 0

Step-by-step explanation:

$\sqrt{6 {x}^{5} {y}^{4} } \times \sqrt{3 {x}^{2}y } \\ \\ = \sqrt{6 {x}^{5} {y}^{4} \times 3 {x}^{2}y } \\ \\ = \sqrt{18 {x}^{7} {y}^{5} } \\ \\ = \sqrt{18 {x}^{7} {y}^{5} } \\ \\ = \sqrt{9 \times 2 \times {x}^{6} \times x \times {y}^{4} \times y } \\ \\ = 3 {x}^{3} {y}^{2} \sqrt{2xy}$

igor_vitrenko [27]4 years ago

7 0

Answer:

This is what i get

Step-by-step explanation:

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Researchers wondered if there was a difference between males and females in regard to some common annoyances. They asked a rando

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The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

D) The data come from a Population that is Normally distributed

F) the samples are independent

c)

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Step-by-step explanation:

Given data Among the 530 males surveyed, 175 responded "Yes

The sample proportion of males

$p_{m} ^{-} = \frac{x}{n} = \frac{175}{530} = 0.3301$

The sample proportion of 575 Females surveyed, 218 responded "Yes

$p_{fem} ^{-} = \frac{x}{n} = \frac{218}{575} = 0.3791$

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

The data come from a Population that is normally distributed.

The two samples are independent

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

We will use two samples Z - hypothesis test

$Z = \frac{p^{-} _{m} - p^{-} _{fem} }{se(p^{-} _{m}-p^{-} _{fem} ) }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{p_{m}(1-p_{m}) }{n_{m} }+\frac{p_{fem} (1-p_{fem} )}{n_{fem} } }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{0.3301(1-0.3301) }{530 }+\frac{0.3791(1-0.3791)}{575} }$

$Se(p_{m} ^{-} - p^{-} _{fem} ) = \sqrt{0.000826} = 0.0287$

The test statistic

$Z = \frac{0.3301-0.3791}{0.02875}$

Z = -1.7043

|Z| = |-1.7043|

The tabulated value Z₀.₉₅ = 1.96

The calculated Z= 1.7043 < 1.96 at 0.05 level of significance

The null hypothesis is accepted

Conclusion:-

The evidence suggest not a higher proportion of females are annoyed by this behavior

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3 years ago