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natima [27]
3 years ago
7

Can any one help me on these two PleaseI

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0

Step-by-step explanation:

\sqrt{6 {x}^{5}  {y}^{4} }  \times  \sqrt{3 {x}^{2}y }  \\  \\  =  \sqrt{6 {x}^{5}  {y}^{4} \times 3 {x}^{2}y  } \\  \\  =  \sqrt{18 {x}^{7} {y}^{5}  } \\  \\  =  \sqrt{18 {x}^{7} {y}^{5}  }  \\  \\  =  \sqrt{9 \times 2 \times  {x}^{6} \times x \times  {y}^{4}  \times y }  \\  \\  = 3 {x}^{3}  {y}^{2}  \sqrt{2xy}

igor_vitrenko [27]3 years ago
7 0

Answer:

This is what i get

Step-by-step explanation:

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An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 3ft long with a diameter of 2.2 ft . S
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4 minutes 34 seconds will takes to empty the tank, if the starts completely full and oil drained at a rate of 2.5 ft^{3} per minute.

Step-by-step explanation:

              The given is,

                         Tank is shaped like a cylinder that is 3 ft long with a diameter of 2.2 ft.

                          Oil drained at a rate of 2.5 ft^{3} per minute.

Step:1

       Time taken to dry the oil tank is,

                           T   = \frac{Volume of oil}{Oil drain rate}  ....................................(1)

Step:2

      Volume of the oil is,

                           V = \pi  r^{2} h.................................................(2)

      Where, r - Radius of Cylinder

                             r = \frac{d}{2}

                             r = \frac{2.2}{2}

                             r = 1.1 ft

      From eqn (1),

                        V =  \pi × 1.1^{2} × 3

                           = 11.40398 ft^{3}

Step:3

     From equation (1)

                           = \frac{11.40398}{2.5}

                           = 4.56

                           = 4.56 minutes

                      T  = 4 minutes 34 seconds

Result:

      Time taken to dry the oil tank is 4 minutes 34 seconds, if a cylinder is 3 ft long with a diameter of 2.2 ft and oil is drained at a rate of 2.5ft^3 per minute.

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