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3 years ago

Can any one help me on these two PleaseI

Mathematics

2 answers:

Inessa05 [86]3 years ago

8 0

Step-by-step explanation:

$\sqrt{6 {x}^{5} {y}^{4} } \times \sqrt{3 {x}^{2}y } \\ \\ = \sqrt{6 {x}^{5} {y}^{4} \times 3 {x}^{2}y } \\ \\ = \sqrt{18 {x}^{7} {y}^{5} } \\ \\ = \sqrt{18 {x}^{7} {y}^{5} } \\ \\ = \sqrt{9 \times 2 \times {x}^{6} \times x \times {y}^{4} \times y } \\ \\ = 3 {x}^{3} {y}^{2} \sqrt{2xy}$

igor_vitrenko [27]3 years ago

7 0

Answer:

This is what i get

Step-by-step explanation:

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If johnny gets 2 apples every 5 minuets how much apples does johnny have in 8 hours.

hodyreva [135]

Answer:

192

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1 year ago

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Afina-wow [57]

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Step-by-step explanation:

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3 years ago

The vertex of this parabola is at (2, -4). When the y-value is -1, the x-value is 3. What is the coefficient of the squared term

rjkz [21]

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, - 4) , thus

y = a(x - 2)² - 4

To find a substitute (3, - 1 ) into the equation

- 1 = a(3 - 2)² - 4 ( add 4 to both sides )

3 = a

Thus

y = 3(x - 2)2 - 4 ← equation in vertex form

= 3(x² - 4x + 4) + 4

= 3x² - 12x + 12 + 4

= 3x² - 12x + 16 ← equation in standard form

with coefficient of x² term = 3

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3 years ago

What is the property to this problem ab+ac=(b+c)a

ryzh [129]

Answer:

Distributive Property of Multiplication

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3 years ago

Read 2 more answers

Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$

$P(X\leq3) =0.944444369992\approx 0.94$

Hence, the required probability is 0.94

4 0

2 years ago